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3 years ago

Solve by substitution: -5x + y = -2 -3x + 6y = -12 please explain

Mathematics

1 answer:

fomenos3 years ago

4 0

First we pick the equation. Let's say we pick first one. From it we express y.

$-5x+y=-2\Longrightarrow y=-2+5x$

Then we use this y and plug it in instead of y in the second equation.

$-3x+6(-2+5x)=-12$

Now just solve for x.

$-3x-12+30x=-12 \\-3x=-30x \\\underline{x=10}$

We plug this x in the first equation.

$-5\cdot10+y=-2$

And solve for y.

$-50+y=-2 \\\underline{y=48}$

So the solution to the equation is geometrically a point P which lies on the intersection of the two lines.

$\boxed{P(10,48)}$

Hope this helps.

r3t40

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Which of the following systems of linear inequalities is represented by the

algol [13]

Answer:

Option D is correct.

Step-by-step explanation:

Option D is correct.

y < 2 and y >= x

Because the dotted line shows that y < 2 and y >=x is shown is represented by diagonal line.

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3 years ago

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Write an equation, solve and show all work.

AnnZ [28]

Answer:

56.

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46+10=56

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3 years ago

A farmer has a soybean field with an area of 55 square meters and a cornfield with an area of 58 square meters. he also has a wh

dexar [7]

A farmer has order the fields from least area to greatest area is,

Soybean field < Cornfield < Wheat field.

Based on the given conditions,

A farmer has a soybean field with an area = 55 square meters

A farmer has a corn field with an area = 58 square meters

He also has a wheat field that is 52 times the size of the soybean field.

So,

We can write,

52 times the size of the soybean field.

That means,

= 55 * 52

Calculate the product or quotient,

= 2860

Wheat field = 2860

Hence,

Soybean field = 55

Cornfield = 58

Wheat field = 2860

Soybean field < Cornfield < Wheat field

Therefore,

A farmer has order the fields from least area to greatest area is,

Soybean field < Cornfield < Wheat field.

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5 0

1 year ago

Pls give an explanation w your answer

Shalnov [3]

$a^{\frac{1}{n}}=\sqrt[n]{a}\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\a^n\cdot a^m=a^{n+m}$
therefore
$64^\frac{1}{4}=\left(2^6\right)^\frac{1}{4}=2^{6\cdot\frac{1}{4}}\\\\=2^\frac{6}{4}=2^{1\frac{2}{4}}=2^{1+\frac{2}{4}}=2\cdot2^\frac{2}{4}\\\\=2\sqrt[4]{2^2}=2\sqrt[4]4$
Other method:
$64^\frac{1}{4}=\sqrt[4]{64}=\sqrt[4]{16\cdot4}=\sqrt[4]{16}\cdot\sqrt[4]4=2\sqrt[4]4$

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3 years ago

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Please Help!!!!!! Use what you've learned today about the sum of the interior angles of triangles and quadrilaterals to determin

sveta [45]

Answer:

m = 116

x = 24

y = 76

z = 40

Step-by-step explanation:

For startes the interior angles of triangles always add up to 180 degrees.

That means....

73 + 83 + x = 180

z + m + x = 180

z + y + 64 = 180

Another important fact is that two angles that are intersected by a line in the case 64 and m always add up to 180 degrees.

So m + 64 = 180

Let's start with 73 + 83 + x = 180

If you add 73 and 83 you get 156

x + 156 = 180 then subtract 156 from both sides and

x = 24

Then use m + 64 = 180 subtract 64 from both sides and

m = 116

z + m + x = 180 become

z + 116 + 24 = 180

Add 116 and 24 and you get 140

z + 140 = 180 subtract 140 from both sides and

z = 40

Check to make sure m + x + z = 180

24 + 40 + 116 = 180

z + y + 64 = 180 becomes

y + 40 + 64 = 180

40 + 64 = 104 so

y + 104 = 180 subtract 104 from both sides and

y = 76

Congratulations you have found all of the angles!

6 0

3 years ago