Someone help me with this pls
1 answer:
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We have that
using a graph tool
see the attached figure
The horizontal asymptote of this function is at <span>y=3</span><span>.
So,
the range of this function is from </span><span>(−∞,3<span>)</span></span>
using a graph tool
see the attached figure
The horizontal asymptote of this function is at <span>y=3</span><span>.
So,
the range of this function is from </span><span>(−∞,3<span>)</span></span>
Given:
The focus of the parabola is at (6,-4).
Directrix at y=-7.
To find:
The equation of the parabola.
Solution:
The general equation of a parabola is:
...(i)
Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.
The focus of the parabola is at (6,-4).
On comparing both sides, we get
...(ii)
Directrix at y=-7. So,
...(iii)
Adding (ii) and (iii), we get
Putting in (ii), we get
Putting in (i), we get
Therefore, the equation of the parabola is .