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Olenka [21]
2 years ago
10

X - y = 4

Mathematics
2 answers:
IrinaK [193]2 years ago
8 0

Answer:

3. 6

Step-by-step explanation:

X - y = 4 ( Equation 1 )

X + y =8 ( Equation 2 )

equation 1 + equation 2

; 2x = 12

x = 12÷2

x =6

hope it helps ☺️

Juliette [100K]2 years ago
4 0

Answer: n=6

Step-by-step explanation:

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Do you A) Mutiply B) Add C) Subtract or D) Divide when using unit rates
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(b) how many measurements must be averaged to get a margin of error of ±0.0001 with 98% confidence? (round your answer up to the
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Given that the scale readings of the laboratory scale is normally distributed with an unknown mean and a standard deviation of 0.0002 grams.

Part A:

If the weight is weighted 5 times and the mean weight is 10.0023 grams, the 98% confidence interval for μ, the true mean of the scale readings is given by:

98\% \ C. \ I.=\bar{x}\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right) \\  \\ =10.0023\pm2.33\left(\frac{0.0002}{\sqrt{5}}\right) \\  \\ =10.0023\pm2.33(0.000089) \\  \\ =10.0023\pm0.00021 \\  \\ =(10.0023-0.00021, \ 10.0023+0.00021) \\  \\ =(10.0021, \ 10.0025)

Thus, we are 98% confidence that the true mean of the scale readings is between 10.0021 and 10.0025.



Part B:

To get a margin of error of +/- 0.0001 with a 98% confidence, then

\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right)=\pm0.0001 \\ \\ \Rightarrow2.33\left(\frac{0.0002}{\sqrt{n}}\right)=0.0001 \\  \\ \Rightarrow\left(\frac{0.0002}{\sqrt{n}}\right)= \frac{0.0001}{2.33} =0.0000429 \\  \\ \Rightarrow\sqrt{n}= \frac{0.0002}{0.0000429} =4.66 \\  \\ \Rightarrow n=4.66^2=21.7156\approx22

Therefore, the number of <span>measurements that must be averaged to get a margin of error of ±0.0001 with 98% confidence is 22.</span>
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3 years ago
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UkoKoshka [18]
The answer is the chart attached

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