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charle [14.2K]
3 years ago
14

PLEASE HELP GUYS ARE BOTH THESE CORRECT!

Mathematics
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

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What is 3/8 equal to in decimals..?
MrRissso [65]

Answer: 0.375

Step-by-step explanation:

Hey there! If you have any questions feel free to leave them in the comments below.

To find the answer you would divide the numerator by the denominator. \frac{3}{8} would be equal to 0.375

~I hope I helped you :)~

3 0
3 years ago
Read 2 more answers
An architect designs a rectangular flower garden such that the width is exactly two-thirds of the length. If 340 feet of antique
KIM [24]

Answer:

The dimensions of the garden is 102 feet by 68 feet

Step-by-step explanation:

Here, we want to get the width and length of the garden

The perimeter is represented by the length of the fencing

From the question;

w = 2l/3

The formula for the perimeter is;

P = 2(l + w)

Thus;

340 = 2(l + 2l/3)

170 = (l + 2l/3)

Multiply through by 3

510 = 3l + 2l

5l = 510

l = 102 feet

w = 2/3 * l

w = 2/3 * 102

w = 68 feet

7 0
3 years ago
Q
katrin2010 [14]

Answer:

v= -(-v)

Step-by-step explanation:

3 0
3 years ago
Answers choices<br> &lt;1<br> &lt;4<br> &lt;2<br> &lt;3
Maslowich

Answer:

B) 4

Step-by-step explanation:

1. <em>It is either 3 or 4</em>, since those are only two angles comparing the lighthouse and the boat.

2. The angle of depression is noted below the horizontal and above the actual line, and out of 3 and 4, <em>4 is the only angle that is below its corresponding horizontal</em>.

So, the angle of depression from the lighthouse to the boat is 4.

7 0
3 years ago
The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th
Fantom [35]

Answer:

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C

Step-by-step explanation:

To find:

∫6x^5(x^6-2)\,dx

Solution:

Method of substitution:

Let x^6-2=t

Differentiate both sides with respect to t

6x^5\,dx=dt

[use (x^n)'=nx^{n-1}]

So,

∫6x^5(x^6-2)\,dx = ∫ t\,dt = \frac{t^2}{2}+C_1 where C_1 is a variable.

(Use ∫t^n\,dt=\frac{t^{n+1} }{n+1} )

Put t=x^6-2

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1

Use (a-b)^2=a^2+b^2-2ab

So,

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C

where C=2+C_1

Without using substitution:

∫6x^5(x^6-2)\,dx = ∫6x^{11}-12x^5\,dx = \frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C

So, same answer is obtained in both the cases.

7 0
3 years ago
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