Jose sold 102 raffle tickets for his basketball team. If he was given 125 tickets to sell, about what percentage of his tickets
1 answer:
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This should have been worth more points, but anyways, here are the answers. Please give thanks :)
1.)Y = 5 - 3X<span>
2.) Y= </span><span>3X - 4</span><span>
3.) Y = 7 - X
4.) Y = -5X
5.) Y = </span>X +6 <span>
6.) Y = 5 -3X
7.) Y = 2 +</span>
<span>X
8.) </span>Y =
X - 3<span>
9.) Y= 2 - [</span>tex] \frac{2}{3} [/tex]<span>
10.) Y = 1 - 5X
11.) Y = 2 - </span>
<span>X
12.) Y = -5 -2X
13.) Y = X - 6
14.) Y = </span>
<span> -2X
15.) Y = 2 +</span><span>X
16.) Y = 2 +</span><span>X
17.) Y = 1 - 5X
18.) Y = </span>[<span>tex] \frac{3}{4} [/tex]</span>X + 2
1.)Y = 5 - 3X<span>
2.) Y= </span><span>3X - 4</span><span>
3.) Y = 7 - X
4.) Y = -5X
5.) Y = </span>X +6 <span>
6.) Y = 5 -3X
7.) Y = 2 +</span>
8.) </span>Y =
9.) Y= 2 - [</span>tex] \frac{2}{3} [/tex]<span>
10.) Y = 1 - 5X
11.) Y = 2 - </span>
12.) Y = -5 -2X
13.) Y = X - 6
14.) Y = </span>
15.) Y = 2 +</span>
16.) Y = 2 +</span>
17.) Y = 1 - 5X
18.) Y = </span>[<span>tex] \frac{3}{4} [/tex]</span>X + 2
Check the picture below.
so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.
