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Varvara68 [4.7K]
2 years ago
5

2. (10.03)

Mathematics
1 answer:
faust18 [17]2 years ago
3 0

This question is incomplete because it was not written properly

Complete Question

A teacher gave his class two quizzes. 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first one passed the second quiz? (2 points)

a) 20%

b) 40%

c) 60%

d) 75%

Answer:

d) 75%

Step-by-step explanation:

We would be solving this question using conditional probability.

Let us represent the percentage of those who passed the first quiz as A = 80%

and

Those who passed the first quiz as B = unknown

Those who passed the first and second quiz as A and B = 60%

The formula for conditional probability is given as

P(B|A) = P(A and B) / P(A)

Where,

P(B|A) = the percent of those who passed the first one passed the second

Hence,

P(B|A) = 60/80

= 0.75

In percent form, 0.75 × 100 = 75%

Therefore, from the calculations above, 75% of those who passed the first quiz to also passed the second quiz.

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pogonyaev

Answer:

<em>x = 7</em>

Step-by-step explanation:

Simplifying

17 = 3X + -4

Reorder the terms:

17 = -4 + 3X

Solving

17 = -4 + 3X

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-3X' to each side of the equation.

17 + -3X = -4 + 3X + -3X

Combine like terms: 3X + -3X = 0

17 + -3X = -4 + 0

17 + -3X = -4

Add '-17' to each side of the equation.

17 + -17 + -3X = -4 + -17

Combine like terms: 17 + -17 = 0

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Combine like terms: -4 + -17 = -21

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Simplifying

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3 years ago
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Let's call the two numbers a and b. So we know that the difference of the two numbers is 36:

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We can use either of these equations to solve for one of the variables in terms of the other variable. Let's use the first and solve for a:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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