Ask question

Ask question

All categories

2 years ago

8

A worker gets paid overtime at the rate of normal time plus one third. One week he works 40 hours of normal time and 6 hours ove

rtime. If his hourly rate is $15 how much did he earn for that week?

1 answer:

Leya [2.2K]2 years ago

5 0

Answer:

$ 720

Step-by-step explanation:

Normal time $ 15

Overtime: 15 x 1/3 = $5 + $15 = $20

(40 x 15) + (6 x 20) = 600 + 120

You might be interested in

An arithmetic sequence has a1 = 22 and a8 = 43. Find a15.

brilliants [131]

The 15th term of the arithmetic sequence $a_{15} = 64$

Option B is correct

The nth term of an arithmetic sequence is given as:

$a_{n} = a + (n - 1)d$

The first value, a = 22

$a_8 = a+(8 - 1)d\\a_8 = a + 7d$

Since $a_8 = 43$

$43 = 22 + 7d\\7d = 43 - 22\\7d = 21\\d = \frac{21}{7}\\d = 3$

The common difference, d = 3

$a_{15}= a + (15-1)d\\a_{15} = a + 14d\\a_{15} = 22 + 14(3)\\a_{15} = 22 + 42\\a_{15} = 64$

The 15th term of the arithmetic sequence = 64

Learn more here: brainly.com/question/24072079

4 0

1 year ago

Can someone please help asap

creativ13 [48]

Answer:

I'd have to say, C: 13

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A line passes through the point (-10,8) and has a slope of 1/2.

timofeeve [1]

Answer:

the answer is y=1/2x+13

6 0

2 years ago

PLS HALP ASAP =w=!!!! (will mark u teh brainliest if you explain the problem properly and clearly, 20 pts uwu!)

Oksanka [162]

N = 3 i = 2
2 x 2 = 4
3 x 3 = 9
4 + 9 = 13
13 = area

7 0

2 years ago

Find all constants a such that the vectors (a, 4) and (2, 5) are parallel.

Nezavi [6.7K]

Answer:

$\displaystyle a = \frac{8}{5}$ .

Step-by-step explanation:

Two vectors $(x_1,\, y_1)$ and $(x_2,\, y_2)$ are parallel to one another if and only if the ratio between their corresponding components are equal:

$\displaystyle \frac{x_1}{x_2} = \frac{y_1}{y_2}$ .

Equivalently:

$\displaystyle \frac{x_1}{y_1} = \frac{x_2}{y_2}$ .

For the two vectors in this equation to be parallel to one another:

$\displaystyle \frac{a}{4} = \frac{2}{5}$ .

Solve for $a$ :

$\displaystyle a = \frac{8}{5}$ .

$\displaystyle \frac{8}{5}$ would be the only valid value of $a$ ; no other value would satisfy the $\displaystyle \frac{x_1}{y_1} = \frac{x_2}{y_2}$ equation.

4 0

2 years ago