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2 years ago

8

A worker gets paid overtime at the rate of normal time plus one third. One week he works 40 hours of normal time and 6 hours ove

rtime. If his hourly rate is $15 how much did he earn for that week?

1 answer:

Leya [2.2K]2 years ago

5 0

Answer:

$ 720

Step-by-step explanation:

Normal time $ 15

Overtime: 15 x 1/3 = $5 + $15 = $20

(40 x 15) + (6 x 20) = 600 + 120

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Step-by-step explanation:

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$n= p(1-p)(\dfrac{z}{E})^2$

, where z = Critical z-value corresponds to the given confidence interval

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Let p be the population proportion of clear days.

As per given , we have

Prior sample size : n= 150

Number of clear days in that sample = 117

Prior estimate of the population proportion of clear days = $p=\dfrac{117}{150}$

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The critical z-value corresponding to 95% confidence interval = z*= 1.95 (By z-table)

Then, the required sample size will be :

$n= \dfrac{117}{150}(1-\dfrac{117}{150})(\dfrac{1.96}{0.05})^2$

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$n= (0.1716)(39.2)^2$

$n= 263.687424\approx264$

Hence, the sample size necessary to construct this interval =264

Thus the correct option is B. 264

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