A. 1/100 * x = 7
x = 7 * 100/1
x = 700

b. 50/100 * x = 33
x = 33 * 100/50
x = 66

c. 3/100 * 100 = 3

d. x/100 * 200 = 6
2x = 6
x = 3

e. 15/100 * 40 = 6

5 0

2 years ago

Helen plays basketball. For free throws, she makes the shot 78% of the time. Helen must now attempt two free throws. C = the eve

riadik2000 [5.3K]

Answer:

0.6708 or 67.08%

Step-by-step explanation:

Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:

$P(C+D) = P(C) *P(D|C) = 0.78*0.86\\P(C+D) = 0.6708$

There is a 0.6708 probability that Helen makes both free throws.

5 0

3 years ago