Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
radius = 3 feet
rearrange the formula making r the subject
πr³ = V ( multiply both sides by 3 to eliminate fraction )
4πr³ = 3V ( divide both sides by 4π )
r³ = 
= ( 3 × 36π ) / 4π = 3 × 9 = 27
take the cube root of both sides
r = ![\sqrt[3]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D)
= 3
Answer:
#11 : 14 cars
#12 : 8+6+4=18
Step-by-step explanation:
Here total available flowers are a lily,a rose , a carnation , a daisy, a dahlia and an iris that is 6 .
And florist is going to make a five flower arrangement from the given 6 flowers without selecting a daisy. SO he have a total of 5 flowers available .
Therefore required probability = 5/6
