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miv72 [106K]
3 years ago
15

81x^4 write as a square

Mathematics
2 answers:
deff fn [24]3 years ago
6 0

Answer:

(9x^2)^2

Step-by-step explanation:

81 root is 9

Dahasolnce [82]3 years ago
3 0

Answer:

a square what

Step-by-step explanation:

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Can someone help solve
leva [86]

\frac{-18z^{7}y^{5}-9z^{9}y^4+18z^6y^8}{9zy^{2} }= -2z^6y^3-z^8y^2+2z^5y^6


When variables with exponents are divided by each other, you subtract the exponents.

For example:

\frac{x^2}{x^1} = x^{2-1} =x^1

\frac{x^5}{x^3} =x^{5-3} = x^2

8 0
3 years ago
Write cos 53 degrees in terms of sine.
SOVA2 [1]
Cos(x) = sin(90 - x)
cos(53) = sin(90 - 53)
cos(53) = sin(37)
7 0
3 years ago
Find the exact value of sin (arccos (3/5)). For full credit, explain your reasoning.
zloy xaker [14]
The equation for cosine is <span><span><span>cos<span>(x)</span></span>=<span>Adjacent/Hypotenuse
</span></span></span>The inside trig function is <span><span>arccos<span>(<span>3/5</span>)</span></span></span>, which means <span><span><span>cos<span>(x)</span></span>=<span>3/5</span></span></span>. Comparing <span><span><span>cos<span>(x)</span></span>=<span>Adjacent/Hypotenuse</span></span></span> with <span><span><span>cos<span>(x)</span></span>=<span>3/5
</span></span></span>
Find <span><span>Adjacent=3</span></span> and <span><span>Hypotenuse=5.
</span></span>Then, using the Pythagorean theorem, find <span><span>Opposite=?
</span></span>a² = c² - b²
a² = 5² - 3² = 25 - 9 = 16
a = √16 = 4

<span><span>Adjacent=3</span></span><span><span>Opposite=4</span></span><span><span>Hypotenuse=5
</span></span><span>
Plug in the value for sin(x) = opposite/hypotenuse

sin(x) = 4/5 </span>
6 0
3 years ago
Is x+y+1=0 a tangent of both y^2=4x and x^2=4y parabolas?
Lubov Fominskaja [6]

Answer:

  yes

Step-by-step explanation:

The line intersects each parabola in one point, so is tangent to both.

__

For the first parabola, the point of intersection is ...

  y^2 = 4(-y-1)

  y^2 +4y +4 = 0

  (y+2)^2 = 0

  y = -2 . . . . . . . . one solution only

  x = -(-2)-1 = 1

The point of intersection is (1, -2).

__

For the second parabola, the equation is the same, but with x and y interchanged:

  x^2 = 4(-x-1)

  (x +2)^2 = 0

  x = -2, y = 1 . . . . . one point of intersection only

___

If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.

_____

Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.

7 0
3 years ago
Find any 3 (x,y) pairs that are solutions for the equation 2x-5y=10 . Show your work
Alla [95]

Answer:

(0,-2), (5,0) and (10,2).

Step-by-step explanation:

Given equation is 2x-5y=10.

Now we need to find 3 pairs of solutions in (x,y) form for the given equation.

As 2x-5y=10 is a linear equation so we are free to pick any number for x like x=0, 5, 10

Plug x=0 into 2x-5y=10, we get:

2(0)-5y=10

0-5y=10

-5y=10

y=\frac{10}{-5}

y=-2

Hence first solution is (0,-2)

We can repeat same process with x=5 and 10 to get the other solutions.

Hence final answer is (0,-2), (5,0) and (10,2).

5 0
3 years ago
Read 2 more answers
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