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ira [324]
3 years ago
8

Find the sample size necessary in order to be 95% confident when determining the true mean weight within 2 units (EC2). Assume t

hat sample variance is 44. a. 65 b. 157 c. 43 d. 170 e. 89
Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

(c) 43.

Step-by-step explanation:

Given:

Margin of error (E) = 2

Sample variance (s^{2}) = 44

Confidence level = 95%

The z- value at 95% confidence level is 1.96.

The sample using the provided information can be calculated as:

n=(\frac{z(s)}{E})^{2} \\n=\frac{z^{2} s^{2} }{E^{2} } \\n=\frac{1.96^{2} (44) }{2^{2} }\\n= 42.52\\n=43

Hence, the correct option is (c) 43.

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Given sample size of 1488, percentage of those polled own a home be 69% and confidence level be 99%.

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Margin of error is the difference between calculated values and real values.

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If Y varies directly as X and Y= 79 when X= 49, Find Y if X = 9
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