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3 years ago

(3x-2y) (4x+3y) (8x-5y)

Mathematics

1 answer:

scoundrel [369]3 years ago

7 0

Step-by-step explanation:

(3x-2y) (4x+3y) (8x-5y)
(3x(4x+3y)-2y(4x+3y))(8x-5y)
(12x²+9xy-8xy-6y²)(8x-5y)
(12x²+xy-6y²)(8x-5y)
12x²(8x-5y)+xy(8x-5y)-6y²(8x-5y)
96x³-60x²y+8x²y-5xy²-48xy²+30y³
96x³-52x²y-53xy²+30y³

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Write each equation in slope-intercept form.

Alexxx [7]

Answer:

A. y = -3/2x + 1

B. y = -5/3x + 10

C. y = -x + 6/5

Step-by-step explanation:

A. You just have to isolate the y so divide by 4: y = -3/2x + 1

B. 3y = -5x + 30

Divide by 3: y = -5/3x + 10

C. -5x + 6 = 5y

Divide by 5: -1x + 6/5 = y OR y = -x + 6/5

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3 years ago

Read 2 more answers

A survey of households in a small town showed that in 850 of 1,200 sampled households, at least one member attended a town meeti

Iteru [2.4K]

Answer:

Hence the confidence interval is ( 0.6745, 0.7422).

Step-by-step explanation:

Now the given are

Sample size = n = 1200

x = 850

Sample proportion is

$\hat{p}=\frac{x}{n}=\frac{850}{1200}=0.7083$

We have to construct 99% confidence interval for the population proportion.

Formula Used:

$(\hat{p}-E , \hat{p}+E)$

Here E is a margin of error.

$E =Zc\times\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

Zc = 2.58

$E =2.58\times\sqrt{\frac{0.7083*(1-0.7083)}{1200}}\\\\E=2.58\times\sqrt{0.000172}=0.0339$

So confidence interval is ( 0.7083 - 0.0339 , 0.7083 + 0.0339)

= ( 0.6745 , 0.7422).

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3 years ago

Jim needs to divide 750 coupon books equally among 9 stores in which place is the first digit of the whole-number quotient?

notsponge [240]

Step-by-step explanation:

Its 8 the first quotient

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3 years ago

Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe

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Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

$P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798$

The probability is 0.5798 or 57.98%.

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3 years ago

8. A paper bag contains one pink crayon, four yellow crayons, three black crayons and two red crayons. What is the probability o

vivado [14]

Answer:

C 1/2

Add all the crayons together and then see how many red and black crayons there are. which in this case it's half. That is the probability

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3 years ago

(3x-2y) (4x+3y) (8x-5y)​

(3x-2y) (4x+3y) (8x-5y)