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creativ13 [48]
3 years ago
10

Each letter in the word "mathematics" is written on a slip of paper and placed in a box. Lynette chooses a letter from the box,

leaves it out, then picks another letter. What's the probability that Lynette chooses 2 vowels? Simplify your answer.
Mathematics
2 answers:
VikaD [51]3 years ago
6 0

Answer:

3/7 and 1/7 =4/7is the right answer i just did it and put there answers in but all of them was wrong they said theses are the answers

Step-by-step explanation:

Fynjy0 [20]3 years ago
3 0
There are 11 slips of paper in the box, and 4 of them have vowels on them.

Chance of picking a vowel the first time  =  4/11 .

If successful, then there are 10 slips left in the box, and 3 of them are vowels.

Chance of picking a vowel the second time  =  3/10 .

Probability of BOTH events  =  (4/11) x (3/10)  =  12/110  =  10.91%  . 

You might be interested in
n △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP. Find the area of △ABC if the area of △BMP is
monitta

Answer: The area of ABC is 56 m².

Explanation:

It is given that in △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP.

Since point P divides the line AB in 1:3, therefore the area of triangle APC and BPC is also in ratio 1:3. To prove this draw a perpendicular h on AB from C.

\frac{\text{Area of } \triangle BCP}{\text{Area of } \triangle ABC} =\frac{\frac{1}{2}\times BP\times CH}{\frac{1}{2}\times AB\times CH} =\frac{BP}{AB}= \frac{3}{4}

Since the area of BPC is \frac{3}{4}th part of total area, therefore area of APC is  \frac{1}{4}th part of total area.

The point M is the midpoint of CP, therefore the area of BMP and BMC is equal by midpoint theorem.

\text{Area of } \triangle BMP=\text{Area of } \triangle BMC

21=\text{Area of } \triangle BMC

Area of BPC is,

\text{Area of } \triangle BPC=\text{Area of } \triangle BMP+\text{Area of } \triangle BMC

\text{Area of } \triangle BPC=21+21

\text{Area of } \triangle BPC=42

Area of APC is,

\text{Area of } \triangle APC=\frac{1}{3}\times \text{Area of } \triangle BPC

\text{Area of } \triangle APC=\frac{1}{3}\times 42

\text{Area of } \triangle APC=14

Area of ABC is,

\text{Area of } \triangle ABC=\text{Area of } \triangle APC+\text{Area of } \triangle BPC

\text{Area of } \triangle ABC=14+42=56

Therefore, the area of ABC is 56 m².

5 0
3 years ago
PLEASE HELP... What do you do when none of the variables cancel out while solving systems by elimination?
Vitek1552 [10]

Answer:

multiply one or both of the equations until a variable can cancel out

3 0
3 years ago
I NEED HELP ASAP!!!
BlackZzzverrR [31]

Answer:

The number that would go in the blank to get a perfect square trinomial is 18

Step-by-step explanation:

The middle term can always be found by taking twice of the square root of the final term.

2 * √81 = 18

5 0
3 years ago
a square measuring 9 inches by 9 inches is cut from the corners of a square measuring 15 inches by 15 inches what is the area of
Alexandra [31]

Answer:

Step-by-step explanation:

It would be the area of the big square minus the area of the small square.

6 0
3 years ago
What is v?<br> -15V-40 = 23-8V
Andrew [12]

Answer:

V = -9

Step-by-step explanation:

-15V - 40 = 23 - 8V

The objective is to get V alone. To do this, first subtract -15V from both sides. Since -15V is a negative, subtracting it will be adding a positive.

-40 = 23 + 7V

Now that there is only one term with the variable V, subtract 23 from both sides.

-63 = 7V

Finally, divide both sides by 7 to get V completely isolated.

-9 = V.

The final answer is V = -9.

7 0
3 years ago
Read 2 more answers
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