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KengaRu [80]
3 years ago
5

POSSIBLE POINTS 10

Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:

Minimum: 8 Q1: 14 Median: 17.5 Q3: 30 Maximum: 32

Step-by-step explanation:

8, 9, 11, 14, 17, 23, 29,30, 32, 32

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Wallace bought 4 gallons of milk last week because his family drinks a lot of milk. If
Greeley [361]

Answer:

5 days

Step-by-step explanation:

There are 16 quarts in 4 gallons of milk, so if they drink 3 quarts every day just divide 16 by 3 which will give you 5.3 but rounding your answer is 5 days.

I hope this helps!!

3 0
3 years ago
Let X denote the time in minutes (rounded to the nearest half minute) for a blood sample to be taken. The probability mass funct
Basile [38]

This question is incomplete, the complete question is;

Let X denote the time in minutes (rounded to the nearest half minute) for a blood sample to be taken. The probability mass function for X is:

x     0       0.5       1       1.5       2       2.5

f(x)  0.1     0.2     0.3    0.2     0.1       0.1

determine;

a) P( X < 2.5 )

B) P( 0.75 < X ≤ 1.5 )

Answer:

a) P( X < 2.5 ) = 0.9

b) P( 0.75 < X ≤ 1.5 ) = 0.5

Step-by-step explanation:

Given the data in the question;

The probability mass function for X is:

x     0       0.5       1       1.5       2       2.5

f(x)  0.1     0.2     0.3    0.2     0.1       0.1

a) P( X < 2.5 )

P( X < 2.5 ) = p[ x = 0 ] + p[ x = 0.5 ] + p[ x = 1 ] + p[ x = 1.5 ] + p[ x = 2 ]

so

P( X < 2.5 ) = 0.1 + 0.2 + 0.3 + 0.2 + 0.1

P( X < 2.5 ) = 0.9

b) P( 0.75 < X ≤ 1.5 )

P( 0.75 < X ≤ 1.5 ) = p[ x = 1 ] + p[ x = 1.5 ]

so

P( 0.75 < X ≤ 1.5 ) = 0.3 + 0.2

P( 0.75 < X ≤ 1.5 ) = 0.5

3 0
3 years ago
Write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of t
alex41 [277]

Answer:

y = -3x + 8

Step-by-step explanation:

4 0
3 years ago
What is 2+2? plz help meh
Vaselesa [24]

Answer:

4 or FISH

Step-by-step explanation:

7 0
3 years ago
Need help finding intervals where the function is decreasing.
umka21 [38]

f(x)=-5x-5\sin x\implies f'(x)=-5-5\cos x

f is decreasing on some interval (a,b) if f'(x) for all x\in(a,b). Similarly, f is increasing on (a,b) if f'(x)>0 for all x\in(a,b).

On the domain 0\le x\le2\pi, we have

-5-5\cos x=0\implies\cos x=-1\implies x=\pi

as the only critical point. So we need to check the sign of f' on two intervals, (0,\pi) and (\pi,2\pi).

On (0,\pi), pick any test value. Suppose we take x=\dfrac\pi2. Then f'\left(\dfrac\pi2\right)=-5, so f is decreasing on this interval.

On (\pi,2\pi), you'd find that f'>0, so f is increasing on this interval.

8 0
3 years ago
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