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vagabundo [1.1K]
4 years ago
15

kathy is packing her suitcase for a trip. she wants the total weight of the suitcase to be no more than 50 pounds. the total wei

ght so far is 37 1/2 pounds. she wants to add books that weigh 1 3/4 pounds each. which inequality shows the number of books she can add to her suitcase

Mathematics
1 answer:
never [62]4 years ago
7 0
D is the correct answer.

We do not need math in this instance, just knowledge.
We know that the answer will point to 0, not infinity. There are constraints. Also note that 1.75*7=12.25, which means you can fit no more than 7 books in the bag.
What best describes this? Answer Choice D
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Which expression is a difference of squares with a factor of 2x + 5? 4x2 + 10 4x2 – 10 4x2 + 25 4x2 – 25
Shtirlitz [24]

Answer:

  4x^2 -25

Step-by-step explanation:

The other factor of the difference of squares is the "conjugate" of the given one: (2x -5). Then their product is ...

  (2x +5)(2x -5) = (2x)^2 -(5)^2 = 4x^2 -25

5 0
3 years ago
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15 crackers weigh 69 grams. how many kilograms is this?
Marrrta [24]

Answer:

0.069\ kg

Step-by-step explanation:

we know that

1 kg=1,000 g

so

using proportion

Find out how many kilograms are 69 grams

Let

x -----> the weight in kg

\frac{1}{1,000}\frac{kg}{g} =\frac{x}{69}\frac{kg}{g}\\\\x=\frac{69}{1,000}\\\\x=0.069\ kg

6 0
4 years ago
A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th
Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let S(t) be the amount of sugar in the tank at time t. Then S(0)=25.

Sugar is added to the tank at a rate of <em>P</em> lb/min, and removed at a rate of

\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}

Separate variables, integrate, and solve for <em>S</em>.

\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt

\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt

-100\ln\left|P-\dfrac S{100}\right|=t+C

\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t

P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}

\dfrac S{100}=P-Ce^{-100t}

S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}

Use the initial value to solve for <em>C</em> :

S(0)=25\implies 25=100P-C\implies C=100P-25

\implies S(t)=100P-(100P-25)e^{-100t}

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick <em>P</em> such that

S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}

5 0
3 years ago
PLEASE HELP!!! Write an equation for the following scenario.
alexandr402 [8]

Answer:2n + 8 = n-3

Step-by-step explanation:

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Misha Larkins [42]

Answer:

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Step-by-step explanation:

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3 years ago
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