Let's see, if the first one has a Principal of $50, when it doubles the accumulated amount will then be $100,
recall your logarithm rules for an exponential,
now, for the second amount, if the Principal is 500, the accumulated amount is 1000 when doubled,
now, for the last, Principal is 1700, amount is then 3400,
70,000 when a zero is in between you gonna count it
ANSWER(S):
22, 23, 27, 28, 32, 33, 37, 38
EXPLANATION(S):
n/a
Answer:
(g · h)(t) = -6t - 6
Step-by-step explanation:
To find (g · h)(t), multiply g(t) by h(t).
g(t) = 3t + 3
h(t) = -2
(g · h)(t) = (-2)(3t + 3)
(g · h)(t) = -6t - 6
The value of d from the given expression is 15
<h3>Word problem leading to equation</h3>
From the given statement the sum of five times d and five times five is a
hundred is interpreted as;
5d + 5(5) = 100
5d + 25 = 100
Subtract 25 from both sides
5d = 100 - 25
5d = 75
d =15
Hence the value of d from the given expression is 15
Learn more on word problem here: brainly.com/question/13818690
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