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Orlov [11]
2 years ago
8

Solve problems 5 1/2×3 1/3​

Mathematics
1 answer:
makvit [3.9K]2 years ago
6 0
5 1/2 X 3 1/3=18 1/3
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What is 4r + 3r + 7y + 5r - 2y - 6r ?<br><br>A. 5r + 5y<br><br>B. 29r - 27y<br><br>C. 27ry​
Sonja [21]

Step-by-step explanation:

It's 6r+5y. But it's not in the option

3 0
3 years ago
Dafes stickball team has six players.how many different six player battling lineups can they make ifdave must bat second and eit
aalyn [17]
Let us name the players A,Dave,Zack,Paul,E and F 
For the first position there are two candidades ( Zack / Paul ) 
For the second position there is only one candidate i.e. Dave 
For the third place there will be 4 candidates (out of Zack and Paul - 1 as one of them is already taken for the first position and A, E and F total-4) 
For the fourth place there will be 3 candidates ( out of the four available candidates in the 3rd place, one will be taken up for 3rd place ) 
For the fifth place there will be 2 candidates 
Finally, for the last place there will be only one candidate left. 
On multiplying the no. of available cadidates, we get 2 * 1 * 4 * 3 * 2 * 1 = 48 i.e. option (A) 
Please mention minor spelling mistakes 
For the second question: 
Let the no of dotted marbles be 'x' and no of striped marbles be 'y' 
then the equation will become as follows 
(y+6)/x = 3 
and 
(x+6)/y = (2/3) 
On solving the equations, we will get x = 10 and y = 24 
Total balls = 10+24+6 = 40 (option E) 
Answer 3 will be ) For the first edge, he can choose 3 paths 
For the second edge he can choose 2 paths for each path of its first edge's path 
For the third , he is bounded to move on the paths created by the first and the second edges hence 1 path for each path created by the first and the second edge together 
It will be multiplication of all the possibilities of the paths of the three edges differently......... 
i.e. 3 * 2 * 1 = 6 
6 0
3 years ago
How does the speed of a runner vary over the course of a marathon (a distance of 42.195 km)? Consider determining both the time
Tom [10]

Answer:

The observed typical difference value of mode is 100 seconds approximately.

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

Step-by-step explanation:

Fundamentals

Consider that there are x favorable cases to an event E, out of a total of n cases. Then, the probability of that event is written as:

P(E)=  

Total number of cases /Number of favorable cases =  x/n

A histogram is constructed for continuous data, which is divided into classes called bins. The shape of the distribution can be determined from the histogram.

step 1

The provided histogram indicates time difference on xx -axis and frequency of runners on yy -axis. To determine the typical difference value, identify the peaks of the graph.

The histogram is skewed towards right side. The graph indicates that there are few outliers around 700 seconds. For a typical difference value, the value of mode is considered.

The graph indicates that the value of mode is 100 seconds approximately.

The observed typical difference value of mode is 100 seconds approximately.

Explanation

From the histogram, the typical difference value is obtained on the basis of guessing the value of mode which has been approximated to be around 100 seconds.

Step 2

From the histogram, it can be estimated that there are around 10 runners which has negative difference which means approxi8matley 10 runners ran the late distance more quickly than the early distance,

The approximate sample size can be calculated as:

Sample size=90+190+180+160+120+80+60+40+30+20

Thus, the proportion of runners is obtained as:

\begin{array}{c}\\p = \frac{{\left( \begin{array}{l}\\{\rm{Number of runners who has }}\\\\{\rm{negative time difference}}\\\end{array} \right)}}{{{\rm{Total sample size}}}}\\\\ = \frac{{10}}{{970}}\\\\ = 0.01\\\end{array}  

p=  <u> </u>Number of runners who has

<u>     negative time difference   </u>

      Total sample size

​  

=10/970

=0.001

The proportion of runners ran the late distance more quickly than the early distance is approximately 1%

EXPLANATION

The obtained proportion is 0.01. It indicates that there are approximately 1% of the runners who ran late distance more quickly than the early distance is very few.

​  

​  

3 0
3 years ago
Please Help Me With This~JT
andriy [413]

Answer:

Top Row Going Left to Right: Circle, Triangle, Square, Pentagon, Hexagon, Octagon

Bottom Row Going Left to Right, Sphere, Cone, Cylinder, Pyramid, Cube, Triangular Pyramid.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Tell whether the lines through the given points are parallel, perpendicular, or neither. Explain.
mina [271]

Answer:

parallel

Step-by-step explanation:

find the slope of each line

Line 1   (5-2)/(-4-2) = 3/-6 =-1/2

Line 2  (-4--9)/(-6-4)= 5/-10 = -1/2

5 0
3 years ago
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