Answer:
(-6,0)
Step-by-step explanation:
the y-axis is any (x number, 0)
Answer:
2. Sorry, I don't how to put that into words, because i'm trying to use calculators, then figure out how they got their answer.
3. C
Step-by-step explanation:
2. ^
3. to get the difference between two numbers, (100 and 50, for example,) you must just simply have them minus each other, like simple math. 100 - 50 = 50.
So your difference between the number 100, and the number 50, are 50.
Answer:
I THINk i did this but i will try to reamber
Step-by-step explanation:
Answer:
50 feet
Step-by-step explanation:
Perimeter is the sum of all of the lengths of the sides.
A triangle has three sides, and three lengths are given, therefore all the sides are given.
The sum of the sides is 20 + 20 + 10 = 50
So the Perimeter is 50 feet
NOT MY WORDS TAKEN FROM A SOURCE!
(x^2) <64 => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2 so (x^2) - (8^2) < 0 To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y) You can work backwards and verify this is true. so let's set (x^2) - (8^2) equal to zero to find the roots: (x^2) - (8^2) = 0 => (x-8)*(x+8) = 0 if x-8 = 0 => x=8 and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0 so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0 so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.
Hope this helped!
:)
