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3 years ago

9

You might even think it’s not a thing for a 11 year-old, but I got this as my assignment today: 6.22222267/2.1 x 1/2 of 98... Th

is is disaster. Pls help.....

1 answer:

lana [24]3 years ago

4 0

Answer to the question:

145.18519533

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PLZ HELP <br> Which polynomial is written in standard form?

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I’m pretty sure it looks like it’s D

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3 years ago

What is the negative reciprocal of 2

Zinaida [17]

Answer:

- $\frac{1}{2}$

Step-by-step explanation:

The reciprocal of a number n is $\frac{1}{n}$

The negative reciprocal is the negative of this, thus

reciprocal of 2 is - $\frac{1}{2}$

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3 years ago

Ron's recycle shop had an old paper-shredding machine. Business was good, so he bought a new paper-shredding machine. The old ma

levacccp [35]

Answer: 1 hour 20 minutes

Step-by-step explanation:

Given : The old machine could shred a truckload of paper in 4 hours.

Rate of work done by old machine = $\dfrac{1}{4}$

The new machine could shred the same truckload in 2 hours.

Rate of work done by new machine = $\dfrac{1}{2}$

Let 't' be the time taken by both of them working together , then we have the following equation:-

$\dfrac{1}{t}=\dfrac{1}{4}+\dfrac{1}{2}\\\\\Rightarrow\dfrac{1}{t}=\dfrac{1+2}{4}\\\\\Rightarrow\dfrac{1}{t}=\dfrac{3}{4}\\\\\Rightarrow t=\dfrac{4}{3}=1\dfrac{1}{3}\ \text{ hours}$

Since 1 hour = 60 minutes

Then, $\dfrac{1}{3}\ \text{ hours}=\dfrac{1}{3}\times60=20\text{ minutes}$

Hence, it will take 1 hour 20 minutes to shred the same truckload of paper if Ron runs both shredders at the same time.

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4 years ago

A random triangle is formed in some way, such that all pairs of angles have the same joint distribution. what is the correlation

Goryan [66]

Does it has a picture?

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3 years ago

Express the equation in rectangular form<br> a) r = 2sin(2Θ)<br> b) r = 4cos(3Θ)

Dafna11 [192]

Answer:

a. sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b. (x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

Step-by-step explanation:

a) r = 2sin(2Θ)

r* = 2 sin 2 theta

We know sin 2theta = 2 sin theta cos theta

r = 2 * 2 sin theta cos theta

sin theta = y/r and cos theta = x/r

r = 4 y/r * x/r

r = 4xy / r^2

Multiply each side by r^2

r^3 = 4xy

r * r^2 = 4xy

We know r = sqrt(x^2+y^2) and r^2 = (x^2+y^2)

sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b) r = 4cos(3Θ)

we know that cos 3 theta = cos^3(theta) - 3 sin^2(theta) cos(theta)

r = 4 *cos^3(theta) - 3 sin^2(theta) cos(theta)

Factor out a cos theta

r = 4 *cos(theta){ cos^2 (theta) - 3 sin^2(theta) }

We know that sin theta = y/r and cos theta = x/r

r = 4 (x/r) { (x/r)^2 - 3 (y/r)^2}

r = 4 *(x/r) { (x^2/r^2 - 3 y^2/r^2}

Multiply by r

r^2 = 4x { (x^2/r^2 - 3 y^2/r^2}

Multiply by r^2

r^2 *r^2 = 4x { (x^2 - 3 y^2}

r^4 = 4x{ (x^2 - 3 y^2}

We know r^2 = (x^2+y^2)

(x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

5 0

3 years ago