Answer:
About 1.85 seconds and 13.15 seconds.
Step-by-step explanation:
The height (in feet) of the rocket <em>t</em> seconds after launch is given by the equation:

And we want to determine how many seconds after launch will be rocket be 390 feet above the ground.
Thus, let <em>h</em> = 390 and solve for <em>t: </em>
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Isolate:

Simplify:

We can use the quadratic formula:

In this case, <em>a</em> = 8, <em>b</em> = -120, and <em>c</em> = 195. Hence:

Evaluate:

Simplify:

Thus, our two solutions are:

Hence, the rocket will be 390 feet above the ground after about 1.85 seconds and again after about 13.15 seconds.
You just have to plug in each thing:
So f(0):
3(0)^2 - 4 = -4
so its not A
f(-2) and f(2):
3(-2)^2 - 4
3(2)^2 -4
now we don't even have to calculate these, anything to the power of an even number is a positive number so -2^2 and 2^2 both equal 4
B is correct, so you can do the others if you want to check, but if B is true the others shouldn't be true.
Answer:
Lauren tutors 42 students in total
Step-by-step explanation:
She tutors for 6 hours and she teaches 7 students an hour , so we just have to multiply 7 by 6 which is 42
Hope it helps:)