Answer:
40
Step-by-step explanation:
(2x+1/(2x))^5 *(2x -1/(2x))^5
= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2
= (4x^2-1/4(x)^2)^5
now
x =4x^2. ,a = 1/4(x)^2 ,n =5
we have
general term = Cr *x^r *a^(n-r)
= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)
= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)
= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)
= Cr * 4(2r-n) *x(4r-2n)
now for x^2
4r-2n = 2
4r -10=2
4r =12
r = 3
now for coeff
C(5,3) * 4^(2*3-5)
5!/(3!*(5-3)!) * 4
5*4/(2*1)*4
40
Answer:
3x - 4
Step-by-step explanation:
Slope (m): 3
Y-intercept (c): = -4
Equation of Line: Y=mx + c
Y=3x -4
Answer:
a= 1 , b = 1/16 , c = 1/256 , d= 3/2 , e=4/9 , f= 16/81
Step-by-step explanation:
The first table is given as;
x 4⁻ˣ
-1 4
0 1
2 1/16
4 1/256
a= 1 , b = 1/16 , c = 1/256
The second table is given as;
x {2/3}^x
-1 3/2
0 1
2 4/9
4 16/81
d= 3/2 , e=4/9 , f= 16/81
Answer:
(a) $3800
(b) (a) -- April to May
Step-by-step explanation:
<h3>(a)</h3>
The least amount is found at the lowest point on the graph. That point is in May. It is on the line between 3700 and 3900, so the amount is $3800.
The least donation amount is a month is $3800.
__
<h3>(b)</h3>
The greatest month-to-month decrease is found where the line on the graph has the steepest negative slope. There are two segments with negative slope:
- April - May (decrease of $500)
- June - July (decrease of $100)
The decrease from April to May is by far the largest of these two decreases.
The greatest decrease occurred April to May.
