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nordsb [41]
4 years ago
5

Use technology to determine an appropriate model of the data. (0,0), (1,-3), (2,-4), (3,-3), (4,0)

Mathematics
2 answers:
vitfil [10]4 years ago
8 0
We have to plug in the values in those functions.
f ( 0 ) = ( 0 - 2 )² - 4 = 4 - 4 = 0
f ( 1 ) = ( 1 - 2 )² - 4 = 1 - 4 = - 3
f ( 2 ) = ( 2 - 2 )² - 4 = 0 - 4 = - 4
f ( 3 ) = ( 3 - 2 )² - 4 = 1 - 4 = - 3
f ( 4 ) = ( 4 - 2 )² - 4 = 4 - 4 = 0
Answer:
D. f ( x ) = ( x - 2 )² - 4
luda_lava [24]4 years ago
8 0
The answer is the third one I believe. :)
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Please help asap, brainliest,thanks, and 50 points. Thank you soooo much! <3
Anuta_ua [19.1K]

Answers:

1) x^{8} y^{8}

2) y^{3} \sqrt{y}

3) 5x^{4} \sqrt{6}

4) \sqrt{7}

5) \frac{\sqrt{z}}{z}

Step-by-step explanation:

1) \sqrt{x^{16} y^{36}}

Rewriting the expression:

(x^{16} y^{36})^{\frac{1}{2}}

Multiplying the exponents:

x^{\frac{16}{2}} y^{\frac{36}{2}}

Simplifying:

x^{8} y^{8}

2) \sqrt{y^{7}}

Rewriting the expression:

\sqrt{y^{6} y}=(y^{6} y)^{\frac{1}{2}}

Multiplying the exponents:

y^{\frac{6}{2}} y^{\frac{1}{2}}

Simplifying:

y^{3} y^{\frac{1}{2}}=y^{3} \sqrt{y}

3) \sqrt{150 x^{8}}

Rewriting the expression:

\sqrt{(6)(25) x^{8}}

Since \sqrt{25}=5:

5x^{4}\sqrt{6}

4) \frac{7}{\sqrt{7}}

Multiplying numerator and denominator by \sqrt{7}:

\frac{7}{\sqrt{7}} (\frac{\sqrt{7}}{\sqrt{7}})=\frac{7}{7\sqrt{7}}

Simplifying:

\sqrt{7}

5) \frac{5z}{\sqrt{25 z^{3}}}

Rewriting the expression:

\frac{5z}{5z \sqrt{z}}

Simplifying:

\frac{1}{\sqrt{z}}

Since we do not want the square root in the denominator, we can multiply numerator and denominator by \sqrt{z}:

\frac{1}{\sqrt{z}}(\frac{\sqrt{z}}{\sqrt{z}})

Finally:

\frac{\sqrt{z}}{z}

3 0
4 years ago
The coordinate grid shows three points P, Q, and R:
a_sh-v [17]
Distance between Q and R only relies on x-values. So, here we do not need to use the distance formula. 
R (6,-4) = (X1, Y1)
Q (-8,-4)= (X2,Y2)
distance= X1-X2
d= (6-(-8)) = (6+8)= 14 units
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3 years ago
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Answer:

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Step-by-step explanation:

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