Answer:
B) 174.01 feet
Step-by-step explanation:
The relevant trig relation is ...
Cos = Adjacent/Hypotenuse
cos(63°) = (79 ft)/(web length) . . . . . substitute given values
Solving for web length, we have ...
web length = (79 ft)/cos(63°) ≈ 174.01 ft
His web line must be 174.01 ft long.
so what you have to do is multiply 3 and 2 and 3 and -14 which ends up being 6x-42x=, then do 15 times -9 and you then do 15 times -5 and that becomes -135x - (-7) then you show it like this= 6x-42x=135x-(-7) the solution would be 36x=-135 divide 36 each side and you get x= 2.28
Answer: The temperature of the object after one hour is 12.9°C to the nearest tenth of a degree
Step-by-step explanation:
Please see the attachments below
Multiply the denominator of -2 to the other side. So, it will be -2(x-1)/-3.
Do the same thing with -3. So, it will be -3 (x-5).
Then, you come up with:
Add 3x to make it:
Then, subtract 15 by 2, which will give you: