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3 years ago

If you complete the square for the equation 3x2 - 5x = 2, the answer is ( x + 5/6 )2 = 97/36.

Mathematics

1 answer:

Ray Of Light [21]3 years ago

4 0

Answer:

True

Step-by-step explanation:

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It depends on the speed she was going?

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3 years ago

What is the volume of a spherical shell with inner radius 7 and outer radius 8?

yuradex [85]

Answer:

707.9 cm³

Step-by-step explanation:

What is the volume of a spherical shell with inner radius 7 and outer radius 8?

The formula for the volume of a sphere is given as;

= 4/3 × π × r³

From the above question:

inner radius 7 and outer radius 8

Hence, the volume of a sphere with

inner radius 7 and outer radius 8 is calculated as:

V = (4/3 × π × 8³ ) - (4/3 × π × 7³)

V = 4/3 × π ×(8³- 7³)

V = 4/3 × π × (512 - 343)

V = 4/3 × π × 169

V = 707.9055446 cm³

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3 years ago

F(n) = 4(n-1) + 7 fine the first three(3) terms in the sequence show all work

vladimir1956 [14]

........................................

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3 years ago

Read 2 more answers

Round your answer to the nearest hundreth

Juliette [100K]

Answer:

201.06 sq. ft.

Step-by-step explanation:

Area of a circle is found by using the equation:

$A = \pi r^{2}$

Radius = 1/2 (diameter) = 1/2 (16) = 8

So plug in:

$A = \pi (8)^{2}$

A = 64 $\pi$

A = 201.06193

Rounded A= 201. 06

5 0

3 years ago

A, B, and C are points on the circumference of a circle, centre 0. AOB is a diameter of the circle. Prove that angle ACB is 90°

ki77a [65]

Answer:

Kindly refer to explanation.

Step-by-step explanation:

Given that:

A,B and C are 3 points on circumference of circle with centre O.

AOB is diameter.

Kindly refer to the attached image.

To prove:

$\angle ACB = 90^\circ$

Solution:

Let $\angle A = x$ and $\angle B = y$ .

Construction: Join point A with centre O.

Considering $\triangle AOC$ :

Side AO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, $\angle ACO=\angle A=x$

Considering $\triangle BOC$ :

Side BO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, $\angle BCO=\angle B=y$

$\angle ACB = \angle ACO + \angle BCO = x+y$ ...... (1)

Now, in $\triangle ABC:$

Using angle sum property of triangle:

$\angle A + \angle B + \angle ACB =180^\circ\\\Rightarrow x+y+x+y=180^\circ\\\Rightarrow 2(x+y)=180^\circ\\\Rightarrow x+y=90^\circ$

By equation (1):

$\angle ACB = 90^\circ$

Hence proved.

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3 years ago