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dolphi86 [110]
3 years ago
7

Can someone help me solve this equation? will give brainliest

Mathematics
2 answers:
telo118 [61]3 years ago
6 0

Answer:

x=20

Step-by-step explanation:

eimsori [14]3 years ago
5 0

Answer:

x = 20

Step-by-step explanation:

Add 47 to both sides of the equation:

4 = x/5

Multiply both sides of the equation by 5:

x = 20

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Ax + bx - 15 = 0;x<br> How do you solve this?
Pani-rosa [81]

Answer:

Step-by-step explanation:

ax+bx-15=0\\=> (a+b)x-15=0\\=>(a+b)x=15\\=>x=\frac{15}{(a+b)}

7 0
3 years ago
Choose the graph that solve the following system x-4y=2 3x+2y=6
Elanso [62]
X - 4y = 2.....multiply by -3
3x + 2y = 6
-------------
-3x + 12y = -6 (result of multiplying by -3)
3x + 2y = 6
------------add
14y = 0
y = 0

3x + 2y = 6
3x + 2(0) = 6
3x = 6
x = 6/3
x = 2

solution is (2,0).....so the graph that has the two lines intersecting (crossing) at (2,0) is gonna be ur graph
5 0
3 years ago
HELLPPPP!!!
Kamila [148]

A + M = 40

M = 2A + 4

A + 2A + 4 = 40

3A = 40 - 4

3A = 36

A = 12 points

M = 40 - 12

m = 28 points

5 0
3 years ago
Need help on these !! 13 and 14! Please!!
katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is <em>y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.</em>

<em>Step-by-step explanation: </em>

As the general sine function is given by

y=asin(bx+c)+d.......[A]

  • amplitude = a
  • period = 2π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • amplitude = a = 4
  • period = 4π
  • phase shift = -4π/3
  • Vertical shift = d = -2

As  

period = 2π ÷ b  

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2  

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b  

c = b × 4π/3  

c = 1/2 × 4π/3  

c = 4π/6  

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,  

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

y=asin(bx+c)+d

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2            

<em>Note: The graph is also shown in attached diagram.</em>

                                             Question # 14

<em>Answer:</em>

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

<em>Step-by-step explanation: </em>

As the general cotangent function is given by

y=acot(bx+c)+d.......[A]

  • amplitude = a
  • period = π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • period = π
  • phase shift = -π/3
  • Vertical shift = d = 2

As  

period = π ÷ b  

b = π/period

b = π/π ∵ period = 4π

b = 1  

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b  

c = b × π/3  

c = 1 × π/3  

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and   c = π/3 in Equation [A] would bring us the required equation for the given function.

y=acot(bx+c)+d

y = cot(x+π/3)+2

<em>Note: The graph is also shown in attached diagram.</em>

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

7 0
3 years ago
HELP!:
algol [13]

Answer:

she can  spend 3.00 dollar on he last chocolate

Step-by-step explanation:

14.00-3.00=11.00

11.00-5.00=6.00

6.00-2.00=4.00

4.00-1.00=3.00

8 0
3 years ago
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