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2 years ago

Jeffrey needs $200 to buy a new iPod. Right now, he has $75. What percent of the $200 does he have?

Mathematics

2 answers:

nignag [31]2 years ago

7 0

Answer:

If you need help on further questions like this, divide what he has to what he needs or his goal

in order to get 37.5% you have to divide 75/ 200

You will get 0.357 and that is 37.5% this is ABOUT 40% but I reccomend putting 37.5% to be safe.

melisa1 [442]2 years ago

6 0

Answer:

40%

Step-by-step explanation:

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2 years ago

Find the indicated function values for the function below<br> g(x)=9x + 8<br> g(0) =

Dennis_Churaev [7]

Answer:

$g(0) = 8$

Step-by-step explanation:

The problem gives us the following function:

$g(x) = 9x + 8$

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3 years ago

Please Help!!

Genrish500 [490]

Given

$a\sqrt{x+b}+c=d$

we have

$\sqrt{x+b}=\dfrac{d-c}{a}$

Squaring both sides, we have

$x+b=\dfrac{(d-c)^2}{a^2}$

And finally

$x=\dfrac{(d-c)^2}{a^2}-b$

Note that, when we square both sides, we have to assume that

$\dfrac{d-c}{a}>0$

because we're assuming that this fraction equals a square root, which is positive.

So, if that fraction is positive you'll actually have roots: choose

$a=1,\ b=0,\ c=2,\ d=6$

and you'll have

$\sqrt{x}+2=6 \iff \sqrt{x}=4 \iff x=16$

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

$a=1,\ b=0,\ c=10,\ d=4$

and you'll have

$\sqrt{x}+10=4 \iff \sqrt{x}=-6$

Squaring both sides (and here's the mistake!!) you'd have

$x=36$

which is not a solution for the equation, if we plug it in we have

$\sqrt{x}+10=4 \implies \sqrt{36}+10=4 \implies 6+10=4$

Which is clearly false

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3 years ago