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Lady bird [3.3K]
3 years ago
11

I NEED THE HELP ASAP 7TH GRADE PLS

Mathematics
1 answer:
qaws [65]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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Use Cramer’s Rule to solve system of equation.
alisha [4.7K]

\left\{\begin{array}{ccc}5x+2y=4\\3x+4y+2z=6\\7x+3y+4z=29\end{array}\right\\\\A=\left[\begin{array}{ccc}5&2&0\\3&4&2\\7&3&4\end{array}\right]\\\\\det A=5\cdot4\cdot4+3\cdot3\cdot0+2\cdot2\cdot7-7\cdot4\cdot0-3\cdot2\cdot5-3\cdot2\cdot4=54\\W_x=\left[\begin{array}{ccc}4&2&0\\6&4&2\\29&3&4\end{array}\right]\\\det W_x=4\cdot4\cdot4+2\cdot2\cdot29+6\cdot3\cdot0-29\cdot4\cdot0-3\cdot2\cdot4-6\cdot2\cdot4=108

W_y=\left[\begin{array}{ccc}5&4&0\\3&6&2\\7&29&4\end{array}\right]\\\det W_y=5\cdot6\cdot4+3\cdot29\cdot0+4\cdot2\cdot7-7\cdot6\cdot0-29\cdot2\cdot5-3\cdot4\cdot4=-162\\W_z=\left[\begin{array}{ccc}5&2&4\\3&4&6\\7&3&29\end{array}\right]\\\det W_z=5\cdot4\cdot29+3\cdot3\cdot4+6\cdot2\cdot7-7\cdot4\cdot4-3\cdot6\cdot5-3\cdot2\cdot29=324\\\\x=\dfrac{\det W_x}{\det A}=\dfrac{108}{54}=2\\\\y=\dfrac{\det W_y}{\det A}=\dfrac{-62}{54}=-3\\\\z=\dfrac{\det W_z}{\det A}=\dfrac{324}{54}=6

5 0
3 years ago
Please help me i dont know how to do this!
jekas [21]
Slope = 2/3
Y-intercept =(0,-1)
Hope this helps

6 0
3 years ago
2x-2=2(2x-3) HELP, solve for x, show your work​
Shtirlitz [24]

Answer:

PEMDAS: x=2      

2x=4x-4

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x=2

6 0
3 years ago
A force vector M points 3 N in the x-direction and 4 N in the y-direction. What is Vector M’s magnitude?
julsineya [31]

Answer:

5 N.

Step-by-step explanation:

Given that,

A force vector M points 3 N in the x-direction and 4 N in the y-direction.

We need to find the magnitude of vector M. The magnitude of the vector when they are perpendicular to each other is given by :

M=\sqrt{3^2+4^2} \\\\M=5\ N

So, the required magnitude of M is 5 N.

8 0
3 years ago
900 × 129 please help me
Anastasy [175]
900 × 126= 116,100. Hoped this helped.
3 0
3 years ago
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