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diamong [38]
3 years ago
5

How many times does the line y=2 touch the graph? (Ensure to draw your line on the graph)* (1 Point) *​

Mathematics
1 answer:
faust18 [17]3 years ago
7 0

Answer:

3

Step-by-step explanation:

if you draw a line y=2 will touch the graph in 3 points

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Solve for x in the equation x^2-4x-9=29
Kipish [7]
X = 2 + √42,2- √42
decimal form: 8.480741, -4.480741
sorry if my answer isn't right
5 0
3 years ago
What is the solution to the system of equations? {x+2y=10y=12x+3
Marianna [84]

The solution to given system of equations are (x,y) = (\frac{4}{25} , \frac{123}{25})

<em><u>Solution:</u></em>

Given that we have to find solution to the system of equations

<em><u>Given equations are:</u></em>

x + 2y = 10  ------ eqn 1

y = 12x + 3 ------ eqn 2

We can solve the above equations by substitution method

<em><u>Substitute eqn 2 in eqn 1</u></em>

x + 2(12x + 3) = 10

x + 24x + 6 = 10

25x = 10 - 6

25x = 4

x = \frac{4}{25}

<em><u>Substitute the above value of x in eqn 2</u></em>

y = 12(\frac{4}{25}) + 3\\\\y = \frac{48}{25} + 3\\\\y = \frac{48+75}{25}\\\\y = \frac{123}{25}

Thus the solution to given system of equations are (x,y) = (\frac{4}{25} , \frac{123}{25})

5 0
3 years ago
PROVE :<br><br>sin^2(-300°).cos^2 (120)+ cos^2(-240 ).sin^2(390)=1/4​
leva [86]

Step-by-step explanation:

\sin {}^{2} ( - 300)  \cos {}^{2} (120)  +  \cos {}^{2} ( - 240)  \sin {}^{2} (390)  =  \frac{1}{4}

\sin {}^{2} (60)  \cos {}^{2} ( {}^{} 120)  +  \cos {}^{2} (120)  \sin {}^{2} (30)

\frac{3}{4}  \frac{1}{4}  +  \frac{1}{4}  \frac{1}{4}

\frac{3}{16}  +  \frac{1}{16}  =  \frac{4}{16}  =  \frac{1}{4}

3 0
2 years ago
An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of stude
AnnZ [28]

Answer:

60 students

Step-by-step explanation:

The confidence interval of a proportion is given by:

p\pm z*\sqrt{\frac{p*(1-p)}{n} }

Where 'p' is the proportion of students who responded 'yes', 'z' is the z-score for a 95% confidence interval (which is known to be 1.960), and 'n' is the number of students in the sample.

If the confidence interval is from 0.584 to 0.816, then:

p=\frac{0.584+0.816}{2}=0.7 \\0.816-0.584=2*(1.96*\sqrt{\frac{p*(1-p)}{n}}) \\0.116=1.96*\sqrt{\frac{0.7*(1-0.7)}{n}}\\n=16.8966^2*(0.7*0.3)\\n=60\ students

60 students were in the sample.

8 0
3 years ago
What is the length of EF in the right triangle below?
Vinil7 [7]
Your question does not give enough information for me to answer
8 0
3 years ago
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