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garri49 [273]
3 years ago
14

How many four-character alpha-numeric codes are possible if repeated characters are not allowed?

Mathematics
1 answer:
sweet [91]3 years ago
5 0

Answer:

1,413,720

Step-by-step explanation:

Total number of characters = letters + numbers

= 26 + 10

= 36.

So total number of possible codes

= 36P4

=  36!/ (36-4)!

= 36*35*34*33

= 1413720

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A real numbers are numbers that can be found on a number line, they include both rational and irrational numbers.
We can first solve the equation;
x² - 6x + 9 =0, using completing square method;
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