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My name is Ann [436]
3 years ago
7

Which equations for the measures of the unknown angles x and y are correct? Check all that apply. x = cos–1(StartFraction a Over

c EndFraction) x = sin–1(StartFraction c Over b EndFraction) x = tan–1(StartFraction c Over a EndFraction) y = sin–1(StartFraction a Over c EndFraction) y = cos–1(StartFraction c Over b EndFraction)
Mathematics
1 answer:
Dvinal [7]3 years ago
8 0

the answers are:

b. x = sin -1 (c/b)

c. x = tan -1 (c/a)

e. x = cos -1 (c/b)

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Marcus worked and earned $60.27 in 8.2 hours. How much did he earn per hour
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Does anyone know the answer to this?
bezimeni [28]

Hey there!


First, let's find s:

s = (5 + 6 + 7) /2 = 9


Second, let's plug in the numbers into the formula:

A = \sqrt{9(9-7)(9-5)(9-6)}


Third, let's simplify the numbers to get one number under the square root:

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Fourth, we'll find the square root of 216 to get the area:

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3 years ago
What is the equality? Seven feet below sea level is farther below sea level than 4 1/2 feet below sea level
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They are both below sea level?
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Read 2 more answers
A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second. The height h
Masja [62]

Answer:

Step-by-step explanation:

a)The height h after t seconds is given by the equation h(t)=-16t^2+112t+5.

Where 5 represents 5feet above the ground and this is the height from which the rocket was launched.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 112

Vertex = - - 112/32= 3.5

So the rocket will attain maximum height at 3.5 seconds.

It will also take 3.5 seconds to reach the ground. This means it will take a total of 3.5 seconds + 3.5 seconds

= 7 seconds to hit the ground.

b) to find time it will take to be 100 feet above the ground,

-16t^2+112t-95 = 0

Using general quadratic equation formula,

a = -16

b = 112

c = -95

t = [-b+/-√b^2-4ac]/2a

t = [ -112 +/-√112^2-4×-16×-95]/16 × -2

= [-112 +/-√12544-6080]/-32

= (-112+80.4)/-32 or (-112-80.4)/-32

t = 0.9875 or t = 6.0125

So it will take 0.9875 or approximately 1 second to be 100 feet above the ground

7 0
3 years ago
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