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myrzilka [38]
3 years ago
5

The ratio of girls to boys in Jaime's chorus is 2 to 4. If there are 25 girls in her chorus, how many boys are there? *

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

50 boys

Step-by-step explanation:

2/4 = 1/2

25*2=50

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When the fifth term of an arithmetic sequence whose  common difference is D=six and whose first term is a1 =four
kodGreya [7K]

Answer:

28 is the answer

Step-by-step explanation:

in an arithmetic sequence nth term An is given by the equation

an \:  = a1 + (n - 1) \times d

where A1 is first term and d is common difference. thus from the question we have

a5 = 4 + ((5 - 1) \times 6) \\  = 4 + (4 \times 6) \\  = 4 + 24 \\  = 28

5 0
3 years ago
3. Uniform A package delivery service breaks up its shipping charges into weight classes, where the package weights are uniforml
Tamiku [17]

Answer:

a) 50% of packages in this class would weigh less than 11 lbs.

b) 25% would weigh more than 11.5 lbs.

c) The average weight for a package in this class is 11 lbs.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

For this problem, we have that:

a. Suppose one of the shipping classes is 10 to 12 lbs. What proportion of packages in this class would weigh less than 11 lbs?

Uniform distribution from 10 lbs to 12 lbs, this means that a = 10, b = 12.

The answer is P(X \leq 11).

P(X \leq 11) = \frac{11 - 10}{12-10} = 0.5

50% of packages in this class would weigh less than 11 lbs.

b. What proportion would weigh more than 11.5 lbs?

Either a package weighs 11.5 lbs or less, or it weighs more than 11.5 lbs. The sum of the probabilities of these events is decimal 1. So:

P(X \leq 11.5) + P(X > 11.5) = 1

P(X > 11.5) = 1 - P(X \leq 11.5)

P(X > 11.5) = 1 - \frac{11.5-10}{12-10}

P(X > 11.5) = 0.25

25% would weigh more than 11.5 lbs.

c. What would the average weight for a package in this class be?

The mean M of the uniform distribution is:

M = \frac{a+b}{2}

So

M = \frac{10+12}{2} = 11

The average weight for a package in this class is 11 lbs.

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3 years ago
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Answer:

b. 36

Step-by-step explanation:

You have to use Pythagorean theorem. A squared + b squared = c squared.

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Then you find the square root of 225 which is 15. Since you have the length for side c.

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Answer:

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The equation says it all.

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