Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
#To make a fraction into percentage, the easy way is to times the fraction with 100
<h3>The percentage of 9/10</h3>
9/10 × 100 = 90
#and so, the percentage of 9/10 is 90%
<h3>
Answer : 90%</h3>
Answer:
270 degrees counterclockwise rotation/ the last answer
Step-by-step explanation:
reflection over the y axis wouldn't work bc the shape would still be a horizontal rectangle
dilation would change the size of the shape
and translation wouldn't map it correctly bc it would still be turned the wrong way
Answer:
A i think
Step-by-step explanation:
4 friends evenly dividing up a n - slice pizza
So each one get 
slices of pizza.
For example, if n = 12 slice then each friend gets 12/4 = 3 pieces. If Harris ate one slice less then he ate 
=3 -1 = 2 pieces.
So the general expression for slices of pizza did Harris eat is
