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USPshnik [31]
3 years ago
10

Y=2x-2 and 4x+2y=12. solve the equation PLEASE SHOW WORK​

Mathematics
2 answers:
diamong [38]3 years ago
8 0
<h3>The solution as an ordered pair is (x,y) = (2,2)</h3><h3>x = 2 and y = 2 pair up together.</h3>

===============================

Work Shown:

4x+2y = 12

4x+2( y ) = 12

4x+2( 2x-2 ) = 12 ... replace y with 2x-2

4x+2( 2x ) + 2( -2 ) = 12 ... distribution rule

4x+4x-4 = 12

8x-4 = 12

8x-4+4 = 12+4 ... add 4 to both sides

8x = 16

8x/8 = 16/8 ... divide both sides by 8

x = 2 is the first part of the answer

Use x = 2 to find y

y = 2x-2

y = 2(2)-2 ... replace x with 2

y = 4-2

y = 2 is the second part of the answer

Ivenika [448]3 years ago
8 0

Answer:

<h2>x = 2 and y = 2 → (2, 2)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}y=2x-2&\text{subtract 2x from both sides}\\4x+2y=12\end{array}\right\\\\\left\{\begin{array}{ccc}-2x+y=-2&\text{multiply both sides by 2}\\4x+2y=12\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-4x+2y=-4\\4x+2y=12\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad4y=8\qquad\text{divide both sides by 4}\\.\qquad\qquad\boxed{y=2}\\\\\text{Put the value of y to the second equation:}

4x+2(2)=12\\4x+4=12\qquad\text{subtract 4 from both sides}\\4x=8\qquad\text{divide both sides by 4}\\\boxed{x=2}

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During the basketball game Josh Devon and Marco are in the following positions Josh is 16 feet from Devon and Devon is 5 1/3 fee
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First off, actually including the diagram is required if you intend on getting an answer. Thankfully, someone else has posed this question on another site and actually included the diagram. I will first describe the diagram, and then solve the problem.
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The average annual rainfall will be more than 40.6 inches in about 2.1 percent of the years.

<h3>What is the average annual rainfall?</h3>

Generally, the equation for the probability is mathematically given as

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The z score for the probability of 0.979 is 2.034, according to the table of z values.

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In the given equation, replace the values of mu and sigma with their respective values, and then solve for x.

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Read more about average

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