Question

A club with 12 members is to choose three officers president vice-presidents and secretary-treasurer if each office is to be held by one person and no person can hold more than one office in how many ways can those offices be filled

Answer 1

Answer:

12P3 = 1320

Step-by-step explanation:

How you need select three persons of a group of twelve persons, but in the selection each member of the group has a different position, then you need use a permutation

Permutation is defined how

$nPr = \frac{n!}{(n-r)!}$

In our case n = 12 and r = 3

Thus

$12P3 = \frac{12!}{(12-3)!}$

12P3 = 1320