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3 years ago

Every winter I fly home to Michigan it takes five hours what is my average speed

Mathematics

2 answers:

nignag [31]3 years ago

6 0

Well you did not say how many miles you are from Michigan

denis23 [38]3 years ago

3 0

So to find speed, you divide your total distance by the time it took to travel.

3,900 ÷ 5 = 780

You are going at a speed of 780 units per hour. You could always simplify it to seconds by merely dividing your speed by 60.

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Spencer buys a bag of 400 lollipops. Each lollipop has one of three flavors: cherry, watermelon, or grape. Spencer picks 15 loll

slavikrds [6]

Answer:

240 lollipops

Step-by-step explanation:

Cherry probability=9/15=3/5=0.6=60%.

$\frac{3}{5} =\frac{x}{400}$

$5x=1200$

$x=240$

240 of the lollipops should be cherry-flavored.

4 0

3 years ago

. What is the solution of the system of equations 3x + 2y = 4 and -2x + 2y = 24? *

Natalija [7]

Answer:

x= -4

y= -8

This will be the solution

3 0

3 years ago

***no links please***

prisoha [69]

Answer:

3(pi)

Step-by-step explanation:

8.33 (repeating 33) is 8.333333...

3(pi) = 9.42477796...

17/2 = 8.5

sqrt(64) = 8

Answer: 3(pi)

4 0

3 years ago

Read 2 more answers

Evaluate the integral, show all steps please!

zalisa [80]

Answer:

$\dfrac{3}{2} \ln |x-4| - \dfrac{1}{2} \ln |x+2| + \text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{x+5}{(x-4)(x+2)}\:\:\text{d}x$

Take partial fractions of the given fraction by writing out the fraction as an identity:

$\begin{aligned}\dfrac{x+5}{(x-4)(x+2)} & \equiv \dfrac{A}{x-4}+\dfrac{B}{x+2}\\\\\implies \dfrac{x+5}{(x-4)(x+2)} & \equiv \dfrac{A(x+2)}{(x-4)(x+2)}+\dfrac{B(x-4)}{(x-4)(x+2)}\\\\\implies x+5 & \equiv A(x+2)+B(x-4)\end{aligned}$

Calculate the values of A and B using substitution:

$\textsf{when }x=4 \implies 9 = A(6)+B(0) \implies A=\dfrac{3}{2}$

$\textsf{when }x=-2 \implies 3 = A(0)+B(-6) \implies B=-\dfrac{1}{2}$

Substitute the found values of A and B:

$\displaystyle \int \dfrac{x+5}{(x-4)(x+2)}\:\:\text{d}x = \int \dfrac{3}{2(x-4)}-\dfrac{1}{2(x+2)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int ax^n\:\text{d}x=a \int x^n \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies \displaystyle \dfrac{3}{2} \int \dfrac{1}{x-4}- \dfrac{1}{2} \int \dfrac{1}{x+2}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating}\\\\$\displaystyle \int \dfrac{f'(x)}{f(x)}\:\text{d}x=\ln |f(x)| \:\:(+\text{C})$\end{minipage}}$