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2 years ago

Is b = 6 a solution to the inequality b – 3 > 5?

Mathematics

1 answer:

const2013 [10]2 years ago

6 0

Answer:Hlello, my name is woods245.

So you have the problem b - 3>5 and is says that b=6.

So know the problem looks like this. 6 - 3>5.

Step-by-step explanation:

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John wants to find the center of a wall so he can hang a picture. He measures the wall and determines it is 65.25" wide. 65.25"

antiseptic1488 [7]

Option B is correct.

John wants to find the center of a wall so he can hang a picture. He measures the wall and determines it is 65.25" wide.

Here, 65.25" is Quantitative, continuous

There are two types of quantitative data or numeric data: continuous and discrete.

As a general rule, counts are discrete and measurements are continuous. A continuous data can be recorded at many different points (length, size, width, time, temperature, etc.)

So, option B is the answer.

3 0

2 years ago

An economist studying fuel costs wants to estimate the mean price of gasoline in her state on a certain day. On that day, she ta

irina1246 [14]

Answer:

($2.19,$2.39)

Step-by-step explanation:

khan

6 0

2 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

In one area, the lowest angle of elevation of the sun in winter is 24degrees Find the distance x that a plant needing full sun c

sweet [91]

Answer:

round answer is : 10 ft

Step-by-step explanation:

The explanation is in the picture!

5 0

2 years ago

2(x+3)^(2)+8=0 Solve.

olga2289 [7]

Answer:

2i-3

Step-by-step explanation:

2(x+3)²=-8

(x+3)²=-4

x+3=2i

x=2i-3

7 0

2 years ago