<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
<em />
Hence, BC=DC proved.
Answer:
15
Since 9 questions is 60% of the exam, you must find 100%. You could find the value of 10% by dividing 60 by 6. You do the same to 9, divide by 6 to get 1.5. Now that you have the value of 10% you can multiply 10% by 10 to get 100. You also do the same to 1.5. Your answer should be 15, if not check your work again.
Step-by-step explanation:
tan 52 = 180/a; a = 180/tan 52
tan 43 = 180/b; b = 180/tan 43
you need to calculate, a-b = 180/tan 52 - 180/tan 43
substitute the value of tan thetas, and calculate it simply...
If i am understanding the question correctly, x<10
Answer:
8 nickels and 9 dimes
Step-by-step explanation:
If all were dimes, the value would be $1.70. It is $0.40 less than that. Changing a dime for a nickel reduces the value by $0.05, so there must have been $0.40/$0.05 = 8 such changes.
There are 8 nickels and 9 dimes.
_____
<em>Check</em>
8 · 0.05 + 9 · 0.10 = 0.40 + 0.90 = 1.30 . . . the answer checks OK
