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Ilia_Sergeevich [38]
3 years ago
7

Pierce bought 16 ounces of motor oil for $2.24. How much is motor oil per ounce?

Mathematics
2 answers:
solong [7]3 years ago
8 0

Answer:

$0.14

Step-by-step explanation:

Maru [420]3 years ago
7 0

Answer:

0.14

Step-by-step explanation:

2.24÷16=0.14

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Help!!<br><br> which expression is equivalent to (m^5 n /pq^2) ^4
lana66690 [7]
\text{Use:}\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{nm}\\\\......................................................\\\\\left(\dfrac{m^5n}{pq^2}\right)^4=\dfrac{(m^5n)^4}{(pq^2)^4}=\dfrac{(m^5)^4n^4}{p^4(q^2)^4}=\dfrac{m^{20}n^4}{p^4q^8}
8 0
3 years ago
3. The sum of three consecutive numbers<br> is 42. What are the numbers?
Zanzabum

Answer:

13 + 14 + 15

Step-by-step explanation:

n + (n + 1) + (n +2) =42

n + n + n + 1 + 2 = 42

3n + 3 = 42

(subtract 3 from both sides)

3n = 39

(divide both sides by 3)

n = 13

(solve)

n + (n + 1) + (n +2) =42

13 + (13 + 1) + (13 + 2) = 42

13 + (14) + (15) = 42

13, 14, 15

(Hope this helps, have a nice day!)

3 0
3 years ago
Can anyone pls help with this ASAP!!! :((
MrRissso [65]

Answer: I believe your answer is C.

7 0
2 years ago
Read 2 more answers
A car dealership pays $8,550 for a car. They markup the price by 20.4% to get the retail price. What is the retail price of the
marin [14]

Answer:

$10294.20

Step-by-step explanation:

8550 increase 20.4% =

8550 × (1 + 20.4%) = 8550 × (1 + 0.204) = 10294.2

3 0
2 years ago
A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain
AysviL [449]

Answer:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

Step-by-step explanation:

For this case we have the following value:

R = 0.0498 \frac{Kpa}{Km}

We can convert this first to \frac{Kpa}{m} like this:

R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}

Now we use the fact the the pressure is defined as P =\frac{F}{A}, whre P is the pressure, F the force and A the area, so then Kpa= \frac{KN}{m^2} and then we can replace this:

R=0.0000498 \frac{KN}{m^3}

Now from definition of work we know that W= Fd where W is the work, F the force and d the distance, so then is equivalent KN =\frac{KJ}{m}

And if we replace this into the equation we got:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

4 0
3 years ago
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