Did you leave out any part of the problem?
Alright, so since it's to the negative power we essentially have 1/(1/4^(3/2)). After that, we find (1/4)^3=1^3/4^3=1/64 and find the square root of that, which is (sqrt1)/(sqrt64)=1/8. Since the answer is 1/(1/8), we get the answer to be 8
speed = distance / time = 100 m / 50 s = 2 m/sec
Juan average speed is 2 m / sec
(2/5) of (1/3) means to multiply.
(2/5)*(1/3)= 2/15
Answer:
TC (A) = 40x , TC (B) = 500 + 20x
Step-by-step explanation:
Let the number of students be = x
Hall A Total Cost
Relationship Equation, where TC (A) = f (students) = f (x) 40 per person (student) = 40x
Hall B Total Cost
Relationship Equation, where TC (B) = f (students) = f (x) 500 fix fee & 20 per person (student) = 500 + 20x
