3 years ago

Which is a perfect square?

Mathematics

1 answer:

velikii [3]3 years ago

4 0

Answer:

6 squared

Step-by-step explanation:

The square root of a perfect square is a rational number.

You might be interested in

In Triangle ABC, L is the midpoint of AB, M is the midpoint of BC, and N is the midpoint of CA.

VashaNatasha [74]

I’m not doing all that so yeah that’s my answer I

3 0

3 years ago

What are three sets of fractions that can be multiplied to get 15/56?

vredina [299]

Much more than just 3.

3 0

4 years ago

Alice had 3 1/4 pounds of flour at the beginning of the week. At the end of the week, she had 2 3/4 pounds. How much has she use

Evgen [1.6K]

Answer:

1 2/4

Step-by-step explanation:

you have to subtract they

4 0

3 years ago

Find the perimeter of the triangle defined by the coordinates (7, 1), (-6, 1), and (10, 6). (Round to nearest tenth)

matrenka [14]

Answer:

$35.6\ units$

Step-by-step explanation:

we know that

The perimeter of triangle is equal to the sum of the length of the three sides

Let

$A(7, 1), B(-6, 1), C(10, 6)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(7, 1), B(-6, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(-6-7)^{2}}$

$d=\sqrt{(0)^{2}+(-13)^{2}}$

$dAB=13\ units$

Find the distance BC

$B(-6, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10+6)^{2}}$

$d=\sqrt{(5)^{2}+(16)^{2}}$

$dBC=16.8\ units$

Find the distance AC

$A(7, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10-7)^{2}}$

$d=\sqrt{(5)^{2}+(3)^{2}}$

$dAC=5.8\ units$

Find the perimeter

$P=dAB+dBC+dAC$

$P=13+16.8+5.8=35.6\ units$

4 0

3 years ago

Figure ABCD is a parallelogram with point C (−4, 1). Figure ABCD is rotated 90° clockwise to form figure A′B′C′D′. What coordina

Svet_ta [14]

There are certain rules to follow when rotating a point 90 deg clockwise. Since it is given that ABCD is a parallelogram and the coordinates of point C are given, we just have to follow this simple relation:

R(90 deg) : (X,Y) ---> (-Y,X)

Using the given coordinates:
R(90 deg<span>) : (-4,1) ---> (-1,-4)
</span>
Therefore, Point C' will be located at (-1,-4)

6 0

3 years ago