Answer:
And the deviation would be:
Step-by-step explanation:
For this case we have the following distribution given:
X 0 1 2 3 4 5 6
P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02
For this case we need to find first the expected value given by:
And replacing we got:
Now we can find the second moment given by:
And replacing we got:
And the variance would be given by:
And the deviation would be:
Answer:
C. 1000 loss.
Step-by-step explanation:
Let x represent purchase price of each car.
We have been given that a used-car dealer sold one car at a profit of 25 percent of the dealer's purchase price for that car and sold another car at a loss of 20 percent of the dealer's purchase price for that car.
We can represent the car that dealer sold with 25% profit to find purchase price as:
Therefore, the purchase price of 1st car was $16,000.
We can represent the car that dealer sold with 20% loss to find purchase price as:
Therefore, the purchase price of 2nd car was $25,000.
The total purchase price of both cars would be
The total sale price of both cars .
We can see that the sale price of both car is less than purchase price by $1000, so the dealer got a loss of $1000.
Therefore, the dealer's total loss, in dollars, for the two transactions combined was 1000 and option C is the correct choice.