Answer:
The signal would have experienced aliasing.
Step-by-step explanation:
Given that:
the bandwidth of the signal
= 36MHz
= 36 × 10⁶ Hz
The sampling frequency
= 36 × 10⁶ Hz
Suppose the sampling frequency is equivalent to the bandwidth of the signal, then aliasing will occur.
Therefore, according to the Nyquist criteria;
Nyquist criteria posit that if the sampling frequency is more above twice the maximum frequency to be sampled, a repeating waveform can be accurately reconstructed.
∴
By Nyquist criteria, for perfect reconstruction of an original signal, i.e. the received signal without aliasing effect;
Then,

∴
The signal would have experienced aliasing.
Answer:
(-340)/231
Step-by-step explanation:
Simplify the following:
((-34)/33)/(7/10)
Multiply the numerator by the reciprocal of the denominator, ((-34)/33)/(7/10) = (-34)/33×10/7:
(-34×10)/(33×7)
33×7 = 231:
(-34×10)/231
-34×10 = -340:
Answer: (-340)/231
Answer is a :
100 + 300% of 100 = 400
but the markup is more than 300%
ans : a)