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3 years ago

PLEASE HELP,

1 answer:

5 0

What we know:

3.14 pi
radius: 7in.
Result units: in^3, this is the results of in used for radius; no conversion needed
Formula volume of a sphere: (4/3)* pi * r^3

(4/3)(3.14)(7)(7)(7)
(4/3)(3.14)(343)
(4/3)(1077.02)
(1.3)(1077.02) \\repeated 3 infinite
1436.026666\\repeated 6inf

The volume of the sphere is about 1436.0266 in^3

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Step-by-step explanation:

<h3>Appropriate Question :-</h3>

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$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

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Consider again,

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can be rewritten as

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