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NeTakaya
3 years ago
8

HELPP ASAP I WILL GIVE 14 POINTS

Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Given:

A box-and-whisker plot of data set.

To find:

The percentage of the data values that are greater than 80.

Solution:

From the given box-and-whisker plot, it is clear that:

Minimum value = 8

First quartile = 60

Median = 68

Third quartile = 80

Maximum value = 92

We know that the 25% the data value are greater than or equal to third quartile because the third quartile divides the data in 75% to 25% and 80 is the third quartile.

Therefore, about 25% of the data values that are greater than 80.

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Write the slope intercept form of the equation of the line through given points
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Y=-8/3x+6
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Y=-1/4(x-10)^2+28 write in standard form
timama [110]

Answer:

y = -\frac{1}{4}x^{2} + 5x + 3

7 0
3 years ago
PLZ HELP 20 POINTS<br><br> Twenty-five percent of the data falls below the number
natta225 [31]
With finding the data that falls below a percentage, you need to look closely at the words. 

Notice that it said  25% of... that word "of" means to multiply. But, what are you multiplying? Well, if you look more closely at the plot, you'll see that your dot and line is lying on 58. But make sure you put 25 over 100.
 
So, your equation would be set up like this: 58 ÷ x = 100/25
We're using "x" as our way of saying, "We need to find out this number." 

After that, we'll need to multiply both sides of the equation by "x"
 
(58 ÷ x) × x = (100/25) × x

Now that you have your equation, you'll need to divide both sides by 4 to get "x". 

x = 4 ÷ 58

58 ÷ 4 = 14.5

Your answer is 14.5 of the data that falls below the number.



7 0
3 years ago
I need help with Geometry
zepelin [54]

Answer:

The answer is 180 degrees.

Step-by-step explanation:

The rotation that maps one side to an adjacent side is 360°/6 = 60°. This is the least rotation that plots the regular hexagon to the aforementioned. In the least whole number of these minimum rotations, such as three 60° rotations to make 180°, will retain the hexagon identical.

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6 0
3 years ago
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Kite EFGH is inscribed in a rectangle where F and H are midpoints of parallel sides. The area of EFGH is 35 square units. What i
sasho [114]

*see attachment for the figure described

Answer:

5 units

Step-by-step explanation:

==>Given the figure attached below, let where FH and EG intercepted be K.

Since FH are midpoints of parallel lines, KE = KG = x.

Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.

Area of kite = ½ × d1 × d2

Where d1 = KH = 7

d2 = EG = KE + KG = x + x = 2x

Area of kite EFGH = 35

THUS:

35 = ½ × 7 × 2x

35 = 1 × 7 × x

35 = 7x

Divide both sides by 7

35/7 = x

x = 5

4 0
3 years ago
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