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ivann1987 [24]
3 years ago
12

Do 1 and have the same value? Are 12/15 and 8/10 have the same value

Mathematics
1 answer:
Alik [6]3 years ago
8 0

Answer:

Step-by-step explanation:

12=3*2*2

15=5*3

12/15=4/3

8/10=4/5

no, they don't have the same value

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I do no understand this
vovangra [49]

The equation of a line for the given slope is y=\frac{1}{2} x+1.

Solution:

Given data:

Slope (m) = \frac{1}{2}

Point = (–2, 0)

x_1=-2, y_1=0

To find the equation of the given line in the point-slope form:

<u>Point-slope formula:</u>

y-y_1=m(x-x_1)

Substitute the given values in the formula.

$y-0=\frac{1}{2} (x-(-2))

$y=\frac{1}{2} (x+2)

$y=\frac{1}{2} x+\frac{2}{2}

$y=\frac{1}{2} x+1

The equation of a line for the given slope is y=\frac{1}{2} x+1.

5 0
4 years ago
Write the equation of a line in point-slope form that has a slope of -1 and passes through the point (-2, 5).
vivado [14]
The\ point-slope\ form:y-y_1=m(x-x_1)\\----------------------\\m=-1;\ (-2;\ 5)\to x_1=-2;\ and\ y_1=5\\\\\boxed{y-5=-1(x-(-2))\to y-5=-(x+2)}
7 0
4 years ago
Plz help me find this answer
cestrela7 [59]

Answer:

C

You have to check which of numbers is the lowest.

Cheers :D

3 0
3 years ago
Twelve percent of the population is left handed. Approximate the probability that there are at least 20 left-handers in a school
DochEvi [55]

Answer:

Step-by-step explanation:

We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).

p = 12/100 = 0.12

number of success, x = 20

n = 200

the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)

From the binomial probability calculator,

P(x ≥ 20) = 0.84

8 0
4 years ago
Find the roots of:
Elena-2011 [213]

\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \  2x^3-7x^2+8x-3=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

  | 2  -7    8  -3

<u>1 |      2   -5   3</u>

  | 2   -5    3  0

<u> 1 |      2     -3   </u>

    2   -3     0

So the factorization is (x-1)² (2x-3)=0. So:

                     \bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2}  }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \  x^3-x^2-4=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

      |  1  -1  0  -4

  <u>2  |     2  2     </u>

         1  2  2  0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

                   \bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \  6x^3+7x^2-9x+2=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

   | 6    7       9      2

<u>-2 |      -12    10     -2</u>

     6    -5     1       0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

         \bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}

                     \large\displaystyle\text{$\begin{gathered}\sf  \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}

6 0
2 years ago
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