Two numbers that are not integers but that are opposites

Find the common ratio of the geometric sequence 36, 6, 1, 16, ... . Write your answer as an integer or fraction in simplest form

nalin [4]

Answer:

Step-by-step explanation:

The common ratio is the constant found by dividing any term by the previous term.

r=6/36=1/6

r=1/6

I am assuming the 16 at the end of the sequence was a typo. IF 16 was at the end of the sequence it is NOT a geometric sequence as there would not be a common ratio for all terms.

7 0

3 years ago

The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds

boyakko [2]

The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation $h=-16t^2+24t+16$ , where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation $h=-16t^2+24t+16$ , we get,

$0=-16t^2+24t+16$

Switch sides, we have,

$-16 t^{2}+24 t+16=0$

Let us solve the equation using the quadratic formula.

Thus, we have,

$t=\frac{-24 \pm \sqrt{24^{2}-4(-16) 16}}{2(-16)}$

Simplifying, we get,

$t=\frac{-24 \pm \sqrt{576+1024}}{-32}$

$t=\frac{-24 \pm \sqrt{1600}}{-32}$

$t=\frac{-24 \pm 40}{-32}$

Hence, the two values of t are

$t=\frac{-24 + 40}{-32}$ and $t=\frac{-24 -40}{-32}$

Simplifying the values, we get,

$t=\frac{16}{-32}$ and $t=\frac{-64}{-32}$

Dividing, we get,

$t=-\frac{1}{2}$ and $t=2$

Since, t cannot negative values, we have,

$t=2$

Thus, the rock will hit the ground at 2 seconds.

8 0

3 years ago

Hey guys its me again its me ghriuhr9h so more points yaaaaay

RideAnS [48]

Step-by-step explanation:

thanks for the free points!

have a great day!

5 0

3 years ago

Read 2 more answers

Help please really need it fast :)

Serga [27]

Answer:

.4 x .9

Step-by-step explanation:

5 0

3 years ago

triangle AMY ~ MEG , AM = 5 MY=7 AY =3. MEG IS A DILATION of AMY by a scale facyor of 1/3. fimd the perimeter of MEG.

Mademuasel [1]

Answer:

7

Explanation:

From the question, we're told that triangles AMY and MEG are similar. If triangle AMY has sides AM = 5, MY = 7, and AY = 3 then we can find the side lengths of triangle MEG since we're told from the question that it is a dilation of AMY by a scale factor of 1/3.

So all we need to is multiply the corresponding sides of AMY by 1/3, so we'll have;

$\begin{gathered} ME=5\ast\frac{1}{3}=\frac{5}{3} \\ EG=7\ast\frac{1}{3}=\frac{7}{3} \\ MG=3\ast\frac{1}{3}=3 \end{gathered}$

We can then go ahead and find the perimeter of MEG. Note that to find the perimeter of a triangle, we add all the length of its sides;

$\begin{gathered} \text{Perimeter of MEG}=\frac{5}{3}+\frac{7}{3}+3 \\ =\frac{5+7+9}{3} \\ =\frac{21}{3} \\ =7 \end{gathered}$

The perimeter of MEG is 7.

6 0

1 year ago