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3 years ago

Helppppppp!!!!!!!!!!!

Mathematics

1 answer:

kifflom [539]3 years ago

3 0

It’s 8 imma just type random letters cause it has to be longer than 20 letters jfjf

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Which products result in a perfect square trinomial? select three options. (negative x 9)(negative x minus 9) (x y x)(x y x) (2

erastovalidia [21]

The products that result in a perfect square trinomial is (x + y + x)(x + y + x), (2x - 3)(-3 + 2x) and (4y² + 25)(25 + 4y²)

<h3>What is an polynomial?</h3>

A polynomial is an expression that involves only the operations of a<em>ddition, subtraction, multiplication</em> of variables.

A perfect square trinomial is the square of a binomial

(x + y + x)(x + y + x) = (2x + y)²

(2x - 3)(-3 + 2x) = (2x - 3)²

(4y² + 25)(25 + 4y²) = (4y² + 25)²

The products that result in a perfect square trinomial is (x + y + x)(x + y + x), (2x - 3)(-3 + 2x) and (4y² + 25)(25 + 4y²)

Find out more on polynomial at: brainly.com/question/2972832

#SPJ4

4 0

2 years ago

I need help with this as fast as possible thanks bye

makvit [3.9K]

Answer:

153.9

Step-by-step explanation:

You use the formula πr^2 for the area, where r is the radius of the circle which is equal to half the diameter

7 0

3 years ago

What is the derivative of x times squaareo rot of x+ 6?

Dafna1 [17]

Hey there, hope I can help!

$\mathrm{Apply\:the\:Product\:Rule}: \left(f\cdot g\right)^'=f^'\cdot g+f\cdot g^'$
$f=x,\:g=\sqrt{x+6} \ \textgreater \ \frac{d}{dx}\left(x\right)\sqrt{x+6}+\frac{d}{dx}\left(\sqrt{x+6}\right)x \ \textgreater \ \frac{d}{dx}\left(x\right) \ \textgreater \ 1$

$\frac{d}{dx}\left(\sqrt{x+6}\right) \ \textgreater \ \mathrm{Apply\:the\:chain\:rule}: \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx} \ \textgreater \ =\sqrt{u},\:\:u=x+6$
$\frac{d}{du}\left(\sqrt{u}\right)\frac{d}{dx}\left(x+6\right)$

$\frac{d}{du}\left(\sqrt{u}\right) \ \textgreater \ \mathrm{Apply\:radical\:rule}: \sqrt{a}=a^{\frac{1}{2}} \ \textgreater \ \frac{d}{du}\left(u^{\frac{1}{2}}\right)$
$\mathrm{Apply\:the\:Power\:Rule}: \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1} \ \textgreater \ \frac{1}{2}u^{\frac{1}{2}-1} \ \textgreater \ Simplify \ \textgreater \ \frac{1}{2\sqrt{u}}$

$\frac{d}{dx}\left(x+6\right) \ \textgreater \ \mathrm{Apply\:the\:Sum/Difference\:Rule}: \left(f\pm g\right)^'=f^'\pm g^'$
$\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(6\right)$

$\frac{d}{dx}\left(x\right) \ \textgreater \ 1$
$\frac{d}{dx}\left(6\right) \ \textgreater \ 0$

$\frac{1}{2\sqrt{u}}\cdot \:1 \ \textgreater \ \mathrm{Substitute\:back}\:u=x+6 \ \textgreater \ \frac{1}{2\sqrt{x+6}}\cdot \:1 \ \textgreater \ Simplify \ \textgreater \ \frac{1}{2\sqrt{x+6}}$

$1\cdot \sqrt{x+6}+\frac{1}{2\sqrt{x+6}}x \ \textgreater \ Simplify$

$1\cdot \sqrt{x+6} \ \textgreater \ \sqrt{x+6}$
$\frac{1}{2\sqrt{x+6}}x \ \textgreater \ \frac{x}{2\sqrt{x+6}}$
$\sqrt{x+6}+\frac{x}{2\sqrt{x+6}}$

$\mathrm{Convert\:element\:to\:fraction}: \sqrt{x+6}=\frac{\sqrt{x+6}}{1} \ \textgreater \ \frac{x}{2\sqrt{x+6}}+\frac{\sqrt{x+6}}{1}$

Find the LCD
$2\sqrt{x+6} \ \textgreater \ \mathrm{Adjust\:Fractions\:based\:on\:the\:LCD} \ \textgreater \ \frac{x}{2\sqrt{x+6}}+\frac{\sqrt{x+6}\cdot \:2\sqrt{x+6}}{2\sqrt{x+6}}$

$Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions$
$\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{x+2\sqrt{x+6}\sqrt{x+6}}{2\sqrt{x+6}}$

$x+2\sqrt{x+6}\sqrt{x+6} \ \textgreater \ \mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c}$
$\sqrt{x+6}\sqrt{x+6}=\:\left(x+6\right)^{\frac{1}{2}+\frac{1}{2}}=\:\left(x+6\right)^1=\:x+6 \ \textgreater \ x+2\left(x+6\right)$
$\frac{x+2\left(x+6\right)}{2\sqrt{x+6}}$

$x+2\left(x+6\right) \ \textgreater \ 2\left(x+6\right) \ \textgreater \ 2\cdot \:x+2\cdot \:6 \ \textgreater \ 2x+12 \ \textgreater \ x+2x+12$
$3x+12$

Therefore the derivative of the given equation is
$\frac{3x+12}{2\sqrt{x+6}}$

Hope this helps!

8 0

3 years ago

At a football game three out of the first five student that arrived were wearing a jacket based on his information if 300 studen

WARRIOR [948]

Answer:

120 students students could be expected to not be wearing a jacket

Step-by-step explanation:

Based on this, we can work with the assumption that 3/5 of the students that entered the stadium were wearing jackets.

Given that the total population of students that attended the game is 300

This means that 3/5 of the 300 = 180 students.

180 students were estimated to be wearing jackets.

The number of students that were without jackets is 300 - 180 = 120 students

7 0

3 years ago

PLEASE ANSWER ASAP! YOUR ANSWER MUST INCLUDE AN EXPLANATION ON ORDER TO RECEIVE POINTS AND THE BRAINLIEST ANSWER! THANKS!!!

Julli [10]

V=A*h*1/3 - equation to count volume of the pyramid
A=93.5 sq ft
h=6 ft
V=93.5*6*1/3=93.5*2=187 cubic ft

8 0

3 years ago

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Helppppppp!!!!!!!!!!!​

Helppppppp!!!!!!!!!!!