Given:
A spinner marked A, B, C is spun then a 6-sided die is rolled.
To find:
The probability of getting a B and then a 6.
Solution:
We know that,
Total possible values for a spinner are 3. So, the probability of getting B, we get
Total possible values for a die are 6. So, the probability of getting 6, we get
Now, the probability of getting a B and then a 6 is
The required probability is 
.
Therefore, the correct option is D.
Answer:
0.13832
Step-by-step explanation:
I think so if it is so please mark me as brainliest
The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
k=-6
k-4=0
k=4
k=-6 or 4
64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7
so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
Answer:
Step-by-step explanation:
I(x)=P(13x) = 2(13x)²+3(13x) +4
I(x)=P(13x).= 338x²+39x+4
