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Jlenok [28]
3 years ago
12

There are two calculus classes at your school. Both classes have a class average of 75.5. The first class has a standard deviati

on of 10.2 and the second has a standard deviation of 22.5. How do the classes compare?
Question 3 options:

They are about the same.


The second class has higher grades than the first.


The first class' scores are closer together and the second's score are more spread out.


The second class' scores are closer together and the first's score are more spread out.
Mathematics
1 answer:
romanna [79]3 years ago
6 0

Answer:

idk sorry

Step-by-step explanation:

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A variable needs to be eliminated to solve the system of equations below. Choose the
AURORKA [14]
Two different things u can do
Substitution:
X-9y=12
+9y +9y
X=9y+12

-3(9y+12)+9y=36
-27y-36+9y=36
+36 +36
-18y = 72
/-18 /-18
Y = -4


Or whatever this other I’ve is called

-3x-9y=36
-1(X-9y)=(12)-1

-3x-9y=36
-x+9y=-12

-4x=24
X= -6
8 0
2 years ago
Help please
hoa [83]
1.) One hundred twenty-five and forty-seven thousandths

2.) 91/100.

3.) 2769/1000

4.) 0.074

5.) 3.705

6.) 75.69

7.) 0.162 is greater than 0.07

8.) 8.049 is greater than 8.0094

9.) 6

10.) 5.678

11.) 5.7



7 0
2 years ago
What is 119.6<br><img src="https://tex.z-dn.net/?f=%20%5Cdiv%20" id="TexFormula1" title=" \div " alt=" \div " align="absmiddle"
leva [86]
Answer: 39.866

That’s the answer even doe it was easy n u could of just done it
3 0
3 years ago
Which multiplication expression is equal to 2 ÷ 1
Aleks04 [339]

Answer:

A i think but i think not also try it

4 0
2 years ago
There are 15 candidates for 4 job positions.
Veronika [31]

Answer:

32760 ways

Step-by-step explanation:

Given

Number of Candidates = 15

Job Positions = 4

Required:

Number of outcomes

This question represent selection; i.e. selecting candidates for job positions;

This question can be solved in any of the following two ways

Method 1.

The first candidate can be chosen from any of the 15 candidates

The second candidate can be chosen from any of the remaining 14 candidates

The third candidate can be chosen from any of the remaining 13 candidates

The fourth candidate can be chosen from any of the remaining 12 candidates

Total Possible Selection = 15 * 14 * 13 * 12

<em>Total Possible Selection = 32760 ways</em>

<em></em>

Method 2:

This can be solved using permutation method which goes thus;

nPr = \frac{n!}{(n-r)!}

Where n = 15 and r = 4

So;

nPr = \frac{n!}{(n-r)!} becomes

15P4 = \frac{15!}{(15-4)!}

15P4 = \frac{15!}{11!}

15P4 = \frac{15*14*13*12*11!}{11!}

15P4 = 15*14*13*12

15C4 = 32760

<em>Hence, there are 32760 ways</em>

8 0
3 years ago
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