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kozerog [31]
2 years ago
14

At the local bakery, Ariel bought 2 oatmeal cookies for $1.50. Mei bought 12 dozen oatmeal cookies for $4.50.

Mathematics
1 answer:
Viefleur [7K]2 years ago
4 0

Answer:

A=3rd one

B=Yes, Its a straight line through the origin

C=1 cookie costs $0.75

Step-by-step explanation:

The reason why C is $0.75 is because of ratios.

2:$1.5

2 divided by 2=1

2 divided by $1.50=$0.75

$0.75 per cookie

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Delvig [45]

Answer:

1/2b - 5 (the third one)

Step-by-step explanation:

"Denni is five years less..."

this tells us we will need to be subtracting five, which knocks out the other answers.

"..one-half his brothers age."

since b represents the age of his brother, one half his brothers age is 1/2b  

That leaves us with 1/2b - 5

5 0
2 years ago
185g in the ratio 2:3
beks73 [17]

ratio 2:3

2 + 3 = 5

185 / 5 = 37

so

37 x 2 = 74

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Answer

185 g in the ratio 2:3 = 74: 111

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3 years ago
What is the surface area?????
Elenna [48]

The area of a triangle is found using the formula Area = 1/2 x base x height.


Base = 8

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2 years ago
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

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I got 20,737 but I could be wrong so I will attach my algorithm and work.

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