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Lisa [10]
3 years ago
15

Help me please, it would be great

Mathematics
1 answer:
Nastasia [14]3 years ago
4 0
AB²=5²+5²+5²=25+25+25=75
AB=5√3≈8.7
Answer:AB≈8.7
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Solve for bbb.<br> -3b+2.5 = 4−3b+2.5=4
Anna11 [10]
The answer is not possible because both most common factors cancel each other out
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Can someone help me with this it is for mathh.
lapo4ka [179]

Answer: it would be  P=4n

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I will mark brainliest if correct please answer fast I will give 10 points to the first person who answers
attashe74 [19]

Answer:

99\ in^{2}

Step-by-step explanation:

Area of any triangle could be always calculated as base length multiplied by the height perpendicular to the aforementioned base divided by 2. Therefore:

A = 18 * 11 / 2 = 198 / 2 = 99

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3 years ago
What is the difference between bernoulii equation and riccati equation
melisa1 [442]
The Bernoulli equation is almost identical to the standard linear ODE.

y'=P(x)y+Q(x)y^n

Compare to the basic linear ODE,

y'=P(x)y+Q(x)

Meanwhile, the Riccati equation takes the form

y'=P(x)+Q(x)y+R(x)y^2

which in special cases is of Bernoulli type if P(x)=0, and linear if R(x)=0. But in general each type takes a different method to solve. From now on, I'll abbreviate the coefficient functions as P,Q,R for brevity.

For Bernoulli equations, the standard approach is to write

y'=Py+Qy^n
y^{-n}y'=Py^{1-n}+Q

and substitute v=y^{1-n}. This makes v'=(1-n)y^{-n}y', so the ODE is rewritten as

\dfrac1{1-n}v'=Pv+Q

and the equation is now linear in v.

The Riccati equation, on the other hand, requires a different substitution. Set v=Ry, so that v'=R'y+Ry'=R'\dfrac vR+Ry'. Then you have

y'=P+Qy+Ry^2
\dfrac{v'-R'\dfrac vR}R=P+Q\dfrac vR+R\dfrac{v^2}{R^2}
v'=PR+\left(Q+\dfrac{R'}R\right)v+v^2

Next, setting v=\dfrac{u'}u, so that v'=\dfrac{uu''-(u')^2}{u^2}, allows you to write this as a linear second-order equation. You have

\dfrac{uu''-(u')^2}{u^2}=PR+\left(Q+\dfrac{R'}R\right)\dfrac{u'}u+\dfrac{(u')^2}{u^2}
u''-\left(Q+\dfrac{R'}R\right)u'+PRu=0
u''+Su'+Tu=0

where S=-\left(Q+\dfrac{R'}R\right) and T=PR.
3 0
3 years ago
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