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Ksivusya [100]
4 years ago
10

Which sequence is not equivalent to the others?

Mathematics
2 answers:
Gnesinka [82]4 years ago
8 0

Answer with explanation:

Consider the geometrical shape , which is in the first Quadrant

Option 1:

  A reflection across the y-axis, followed by a reflection across the x-axis, and then a 90° clockwise rotation about the origin .

Explanation:  

  When we reflect the shape across y axis , it will reach in second Quadrant, then by reflection across the x-axis,takes it to the third Quadrant,then a 90° clockwise rotation about the origin takes it to the second Quadrant.

Option 2:

a 90° clockwise rotation about the origin and then a 180° rotation about the origin

Explanation:  

90° clockwise rotation about the origin, takes the shape to fourth Quadrant,and then  a 180° rotation about the origin takes the shape to Second Quadrant.

Option 3

a reflection across the x-axis, followed by a 90° counterclockwise rotation about the origin, and then a reflection across the x-axis

Explanation:

a reflection across the x-axis, takes the shape in fourth Quadrant,then a 90° counterclockwise rotation about the origin takes the shape in first Quadrant, and again then a reflection across x axis ,takes the shape again in Fourth Quadrant.

Option 4

a 90° counterclockwise rotation about the origin

Explanation:

a 90° counterclockwise rotation about the origin takes the shape in Second Quadrant.

Option 3 That is , Statement 3,⇒ a reflection across the x-axis, followed by a 90° counterclockwise rotation about the origin, and then a reflection across the x-axis, is not equivalent to the other statement.

Mila [183]4 years ago
6 0
I  THINK its 2. :)                                         Hope i'm right.
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Answer:

See answers below for explanations (answers are in bold)

Step-by-step explanation:

<u>Problem 1 (Top left):</u>

Assuming that the shape is an ellipse, we will use the formula A=πab where a and b are both half the major and minor axis respectively. Since a=9 and b=6, then we have A = π(9)(6) = 54π = 169.646 units^2 as our final answer

<u>Problem 2 (Top right):</u>

Again, we use the same equation as in Problem 1 but this time, a=12 and b=8, so we then have A = π(8)(12) = 96π = 301.593 units^2 as our final answer

<u>Problem 3 (Bottom left):</u>

We can make this irregular shape into a half-ellipse and a rectangle. We would find their separate areas and add them up. The area of the half-ellipse would be A=1/2πab. The value of "a" would be 13.8/2=6.9 since that's the length of the rectangle. The value of "b" would be 3.5, so that means the area of the half-ellipse would be A = 1/2(π)(6.9)(3.5) = 12.075π = 37.935 units^2.  The width and length of the rectangle are 5.4 and 13.8 respectively, so this means the area of the rectangle is 5.4*13.8 = 74.52 units^2. Combining both areas, we get 37.935+74.52 = 112.455 units^2 as our final answer

<u>Problem 4 (Bottom right):</u>

This irregular shape is an ellipse, but a circle is missing from its center. Thus, we must find the area of the circle and ellipse and then subtract the circle's area from the ellipse's area. For the area of the ellipse, a=(15.5/2)=7.75, and b=(7/2)=3.5, making its area A = π(7.75)(3.5) = 27.125π = 85.216 units^2. The area of a circle is A=πr² where "r" is the radius. The radius would be 7/2=3.5, making the circle's area A = π(3.5²) = 12.25π = 38.485 units^2. This means that the shaded area is 85.216-38.435 = 46.781 units^2  

6 0
3 years ago
Please help ASAP I am very dumb​
igomit [66]

Answer:

C

Step-by-step explanation:

calculate like terms, then it is pretty simple from there.

4 0
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